Question

嗨，我正在使用symfony 4和教义。这是我的学说。

public function paginationQueryByAttributes($attributes) {

        $qb = $this->createQueryBuilder("c");
        $qb->select('c');

        if (array_key_exists('model_id', $attributes)) {
            $qb->leftJoin('c.model', 'm.id');
            $qb->andWhere('m.id = ' . $attributes['model_id']);
            unset($attributes['model_id']);
        } elseif (array_key_exists('brand_id', $attributes)) {
            $qb->leftJoin('c.model', 'm');
        }
}

这是我的汽车模型。

<?php

namespace App\Entity;

use App\Model\BaseCar;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Bridge\Doctrine\Validator\Constraints\UniqueEntity;
use Symfony\Component\Validator\Constraints as Assert;
use Swagger\Annotations as SWG;
use JMS\Serializer\Annotation\Groups;

/**
 * @ORM\Entity(repositoryClass="App\Repository\CarRepository")
 * @UniqueEntity("id")
 */
class Car extends BaseCar
{
    /**
     * @ORM\ManyToOne(targetEntity="App\Entity\Model",cascade={"refresh","merge"}, inversedBy="cars")
     * @ORM\JoinColumn(nullable=false)
     */
    protected $model;

    public function getModel()
    {
        return $this->model;
    }

    public /**
 * @param $
 */function setModel( $model)
    {
        $this->model = $model;

        return $this;
    }
}

我这样称呼仓库，

$attributes = $request->request->all();

        $query = $this->getDoctrine()
                ->getRepository(Car::class)
                ->paginationQueryByAttributes($attributes);

我遇到此错误。

[语法错误]行0，列50：错误：预期的字符串结尾，得到了'。'

这是查询...

 SELECT c 
 FROM App\Entity\Car c 
   LEFT JOIN c.model m.id 
   LEFT JOIN m.brand b 
 WHERE m.id = 2 
   AND b.id = 1 
   AND c.code like :code 
   AND c.name like :name

Answer 1

在您加入$qb->leftJoin('c.model', 'm.id');的过程中，m.id部分现在是您的别名。将其更改为$qb->leftJoin('c.model', 'm');

语法错误-第0行，第50行：错误：预期的字符串结尾，为'。'”

1 个答案: