无法在JPAQuery中获得ROW_NUMBER（）

Question

我想将以下查询转换为应用程序中的JPAQuery

"select row_number() OVER (ORDER BY points desc) as rank from points_counter where user_id=?"

所以我通过以下方式结合使用了PathBuilder，OrderSpecifier和SQLExpressions，

PathBuilder<PointsCounter> Counter = new PathBuilder<>(
    PointsCounter.class, "pointsCounter");

OrderSpecifier<BigDecimal> sortOrder = new OrderSpecifier<>(Order.ASC,
    pointsCounter.get("points", BigDecimal.class));

SimpleExpression<Long> rowNumber = SQLExpressions.rowNumber().over().orderBy(sortOrder)
    .as("rownumber");

BooleanExpression predicate = model.entity.identifier.eq(identifier);

JPAQuery<PointsLeaderboardCounter> query = new JPAQuery<>(em);

Long m = query.from(model).where(predicate).select(rowNumber).fetch();

但收到此错误

unknown operation with operator ROWNUMBER and args [] over (order by 
order()) as rownumber
2018-07-10 13:12:43,706 ERROR org.apache.catalina.core.ContainerBase. 
[Tomcat].[localhost].[/].[dispatcherServlet] : Servlet.service() for 
servlet [dispatcherServlet] in context with path [] threw exception 
[Request processing failed; nested exception is 
java.lang.IllegalArgumentException: No pattern found for ROWNUMBER] 
with root cause
java.lang.IllegalArgumentException: No pattern found for ROWNUMBER