对不起,我的英语不是我的母语,所以请不要过多减去我。我是编程的初学者,并且正在从Internet上的教程中学习。今天是我第一次问堆栈溢出问题。这可能是一个愚蠢的问题,我知道有很多类似的问题,但这是一个不同的问题,不是重复的。让我谈我的问题。
我有一个react组件,其中我使用react-plaid npm包来使用Plaid APi。可以在这里找到react-plaid
我当前的组件代码如下
组件
import React, {Component} from 'react';
import BuggyApi from "../../services/BuggyApi";
import BlockUi from "react-block-ui";
import ReactPlaid from 'react-plaid'
class Integration extends Component{
state={
plaid_public_key: "",
plaid_public_token: "",
blocking: false,
isSuccess: false,
errorMessage: [],
open: false,
plaidData: [],
};
componentWillMount(){
new BuggyApi().getPlaidPublicKey().then((response)=>{
console.log(response.data);
if(response.status===200){
this.setState({
plaid_public_key: response.data.public_key
});
}
}).catch((error)=>{
})
}
handleOnExit = (error, metadata)=>{
if (error != null) {
console.log('link: user exited');
console.log(error, metadata);
}
};
handleOnLoad =()=>{
console.log('link: loaded');
};
handleOnEvent =(eventname, metadata)=>{
console.log('link: user event', eventname, metadata);
};
handleOnSuccess = (public_token, metadata) => {
console.log('public_token: ' + public_token);
console.log('account ID: ' + metadata.account_id);
};
componentDidMount(){
const script = document.createElement("script");
script.src = "https://cdn.plaid.com/link/v2/stable/link-initialize.js";
script.async = true;
document.body.appendChild(script);
}
render(){
return(
<div className="page-wrapper">
<div className="content container-fluid">
<div className="row">
<div className="col-xs-8">
<h4 className="page-title">Integration</h4>
</div>
<div className="col-xs-4 text-right m-b-30">
</div>
</div>
<div className="row">
<div className="col-md-12">
<div className="text-center">
<h4 className="modal-title">
Link your bank account
</h4>
</div>
<br/>
<br/>
<form>
{(this.state.isSuccess)?
<div className="row">
<div className="col-sm-6 col-sm-offset-3">
<div className="alert alert-success">
<strong>Success!</strong> Settings updated successfully!
</div>
</div>
</div>:null
}
{(this.state.errorMessage.length>0)?
<div className="row">
<div className="col-sm-6 col-sm-offset-3">
<div className="alert alert-danger">
<ul>
{this.state.errorMessage.map((message,i) =><li key={i}>{message}</li>)}
</ul>
</div>
</div>
</div>:null
}
<BlockUi tag="div" blocking={this.state.blocking}>
<div className="row">
<div className="col-sm-6 col-sm-offset-3">
{(this.state.plaid_public_key!=="")?
<div>
<button onClick={() => this.setState({ open: true})}>Open Plaid</button>
<ReactPlaid
clientName="Arshad"
product={["auth"]}
apiKey={this.state.plaid_public_key}
env='sandbox'
open={this.state.open}
onSuccess={(token, metaData) => this.setState({plaidData: metaData})}
onExit={() => this.setState({open: false})}
/>
</div>:null
}
</div>
</div>
</BlockUi>
</form>
</div>
</div>
</div>
</div>
);
};
}
export default Integration;
问题是,当我单击打开链接按钮时,它仅显示格子模型几秒钟,然后刷新应用程序页面。我想知道是否有人可以提供同样的帮助。
注意:
请忽略公共密钥状态,您可以在apiKey = {this.state.plaid_public_key}中将其设置为“ c10c40c4ee5eee97764307027f74c2”。我正在使用Axious从服务器获取公钥。
答案 0 :(得分:1)
我认为我找到了问题,尽管可以将我的答案发布在stackoverflow上以帮助其他人(如果有人遇到相同的问题)是可以的。我正在将react-plaid-link放在标签内。 react-plaid-link返回一个按钮,根据html标准,该按钮在表单中没有“ type”属性的按钮的作用类似于提交按钮。对于我来说,单击按钮提交表单以刷新页面也是如此。我通过删除标签解决了该问题。我更新的代码如下所示。
import React, {Component} from 'react';
import BuggyApi from "../../services/BuggyApi";
import BlockUi from "react-block-ui";
import ReactPlaid from 'react-plaid'
class Integration extends Component{
state={
plaid_public_key: "",
plaid_public_token: "",
blocking: false,
isSuccess: false,
errorMessage: [],
open: false,
plaidData: [],
};
componentWillMount(){
new BuggyApi().getPlaidPublicKey().then((response)=>{
console.log(response.data);
if(response.status===200){
this.setState({
plaid_public_key: response.data.public_key
});
}
}).catch((error)=>{
})
}
handleOnExit = (error, metadata)=>{
if (error != null) {
console.log('link: user exited');
console.log(error, metadata);
}
};
handleOnLoad =()=>{
console.log('link: loaded');
};
handleOnEvent =(eventname, metadata)=>{
console.log('link: user event', eventname, metadata);
};
handleOnSuccess = (public_token, metadata) => {
console.log('public_token: ' + public_token);
console.log('account ID: ' + metadata.account_id);
};
componentDidMount(){
const script = document.createElement("script");
script.src = "https://cdn.plaid.com/link/v2/stable/link-initialize.js";
script.async = true;
document.body.appendChild(script);
}
render(){
return(
<div className="page-wrapper">
<div className="content container-fluid">
<div className="row">
<div className="col-xs-8">
<h4 className="page-title">Integration</h4>
</div>
<div className="col-xs-4 text-right m-b-30">
</div>
</div>
<div className="row">
<div className="col-md-12">
<div className="text-center">
<h4 className="modal-title">
Link your bank account
</h4>
</div>
<br/>
<br/>
{(this.state.isSuccess)?
<div className="row">
<div className="col-sm-6 col-sm-offset-3">
<div className="alert alert-success">
<strong>Success!</strong> Settings updated successfully!
</div>
</div>
</div>:null
}
{(this.state.errorMessage.length>0)?
<div className="row">
<div className="col-sm-6 col-sm-offset-3">
<div className="alert alert-danger">
<ul>
{this.state.errorMessage.map((message,i) =><li key={i}>{message}</li>)}
</ul>
</div>
</div>
</div>:null
}
<BlockUi tag="div" blocking={this.state.blocking}>
<div className="row">
<div className="col-sm-6 col-sm-offset-3">
{(this.state.plaid_public_key!=="")?
<div>
<button onClick={() => this.setState({ open: true})}>Open Plaid</button>
<ReactPlaid
clientName="Arshad"
product={["auth"]}
apiKey={this.state.plaid_public_key}
env='sandbox'
open={this.state.open}
onSuccess={(token, metaData) => this.setState({plaidData: metaData})}
onExit={() => this.setState({open: false})}
/>
</div>:null
}
</div>
</div>
</BlockUi>
</div>
</div>
</div>
</div>
);
};
}
export default Integration;
答案 1 :(得分:1)
有时您需要将“格子”按钮放在表单元素中,在这种情况下,只需将(e) => e.preventDefault()
作为onClick
处理程序传入
<ReactPlaid
clientName="Arshad"
product={["auth"]}
apiKey={this.state.plaid_public_key}
env='sandbox'
open={this.state.open}
onSuccess={(token, metaData) => this.setState({plaidData: metaData})}
onExit={() => this.setState({open: false})}
onClick={(e) => e.preventDefault()}
/>