Question

有人能为我提供一个示例，说明如何在字典中存储不同的函数，并将int作为键并作为值运行。那么我可以轻松地将函数调用如下：

functionsDictionary[123](string);

注意字典中的所有函数只接受一个字符串输入。并且没有回报。

Answer 1

听起来像是在追求

Dictionary<int, Action<string>>

或可能（基于您的头衔）

Dictionary<uint, Action<string>>

样品：

using System;
using System.Collections.Generic;

class Test
{
    static void Main()
    {
        var dictionary = new Dictionary<int, Action<string>>
        {
            { 5, x => Console.WriteLine("Action for 5: {0}", x) },
            { 13, x => Console.WriteLine("Unlucky for some: {0}", x) }
        };

        dictionary[5]("Woot");
        dictionary[13]("Not really");

        // You can add later easily too
        dictionary.Add(10, x => Console.WriteLine("Ten {0}", x));
        dictionary[15] = x => Console.WriteLine("Fifteen {0}", x);

        // Method group conversions work too
        dictionary.Add(0, MethodTakingString);
    }

    static void MethodTakingString(string x)
    {
    }
}

Answer 2

Dictionary<int, Action<string>> _functions = new Dictionary<int, Action<string>>();
_functions[123]("hello");

如何使用uint作为键在C中存储函数（C＃）

2 个答案: