Question

我正在编写控件视图函数edit_article，以更新模型表title的{{1}}和content的字段：

要更新标题和内容，我雇用了Article

article=form.save

在提交问题时报告错误

def edit_article(request, pk):
    article = Article.objects.get(pk=pk)

    if request.method == "POST":
        form = ArticleForm(data=request.POST)
        print(request.POST)
        if form.is_valid():
           article = form.save()

我没有更改django.db.utils.IntegrityError: (1048, "Column 'owner_id' cannot be null")，只是将其保留为以前的状态。

通过显式重新分配属性来解决该问题：

owner_id

模型if form.is_valid(): # article = form.save() article.title = form.cleaned_data['title'] article.content = form.cleaned_data['content'] article.save()

Article

为什么class Article(models.Model): STATUS = ( (1, 'normal'), (0, 'deleted'), ) owner = models.ForeignKey(User, on_delete=models.CASCADE) block = models.ForeignKey(Block, on_delete=models.CASCADE) title = models.CharField(max_length=100) content = models.TextField() # set the widget status = models.IntegerField(choices=STATUS) date_created = models.DateTimeField(auto_now_add=True) date_updated = models.DateTimeField(auto_now=True) class Meta: ordering = ("id",) def __str__(self): return self.title作为快捷方式失败了？

Answer 1

如果要更新现有记录，则应将该模型的实例对象传递给表单。

因此您的代码将更改为

if request.method == "POST":
    form = ArticleForm(instance=article, data=request.POST)
...

无法使用form.save（）保存对对象的更改

1 个答案: