我在MySQL表中有一些jpg图像。如何显示这些图像?
有人可以通过提供示例代码来帮助我吗?
答案 0 :(得分:2)
<?php
$image = $row['myimage'];
header("Content-type: image/gif");
print $image;
exit;
>?
但是存储路径似乎更容易......
答案 1 :(得分:0)
这个概念有点类似于下面的代码,其中img1.jpg
是一个图像文件
$handle = fopen('img1.jpg', 'r');
header("Content-type: image/gif");//make sure that you dont have output before it
echo fread($handle, filesize('img1.jpg'));
尝试下一个实验
$handle = fopen('img1.jpg', 'r');
echo fread($handle, filesize('img1.jpg'));
//If you are storing the output of this in
//your db then this should work
//however it is best recommended to store
//path which makes you jog a lot easir
//if you get the same error then you have error in
//storing your file