在创建Sass Mixin时需要帮助。
我有一个叫做Vertical3的类,该类将相同的图像彼此叠放3次。我还得到了一个属性调用重叠,其范围从-2到+1,下面将为其定义类。这些重叠的类与纵向3位于同一级别。
如您所见,它们仅调整前两个项目的边距。我想为此定义一个混蛋。
<div class="vertical3 overlap-3">
<img>
<img>
<img>
</div>
.vertical3 {
flex-flow: column;
flex-direction: column-reverse;
justify-content: flex-start;
align-items: center;
img {
max-height: 27%;
}
}
.vertical3.overlap-2 {
img:first-child {
margin-top: -5%;
}
img:nth-child(2) {
margin-top: -5%;
}
}
.vertical3.overlap-1 {
img:first-child {
margin-top: -2.5%;
}
img:nth-child(2) {
margin-top: -2.5%;
}
}
.vertical3.overlap2 {
img:first-child {
margin-top: 5%;
}
img:nth-child(2) {
margin-top: 5%;
}
}
.vertical3.overlap1 {
img:first-child {
margin-top: 2.5%;
}
img:nth-child(2) {
margin-top: 2.5%;
}
}
我想完成这样的事情
.vertical3 {
flex-flow: column;
flex-direction: column-reverse;
justify-content: flex-start;
align-items: center;
img {
max-height: 27%;
}
@inlcude overlap(2.5%)
}
@mixin overlap($base){
adding overlap-2 to overlap2 as classes
}
答案 0 :(得分:1)
我已经创建了下面的代码来展示如何实现此目标。
您将调用mixin并传入要使用的较大的边距值,然后mixin将该值除以2得到较小的边距,并输出所需的所有相关类。
@mixin overlap($base){
&.overlap-2 {
img {
&:first-child, &:nth-child(2) {
margin-top: -(($base) / 2);
}
}
}
&.overlap-1 {
img {
&:first-child, &:nth-child(2) {
margin-top: -($base);
}
}
}
}
.vertical3 {
flex-flow: column;
flex-direction: column-reverse;
justify-content: flex-start;
align-items: center;
background: red;
width: 50px;
height: 50px;
img {
max-height: 27%;
}
@include overlap(5%);
}