Question

所以我有两个对象：

对象1：

{
  "Details": {
    "name": "John"
    "age": 34
  }
}

对象2：

{
  "MoreInfo": {
    "Title": "Mr"
  }
}

我想从这两个对象中创建一个JSON对象，看起来像这样：

{
  "Details1": {
      "Details": {
          "name": "John"
          "age": 34
      }
  },
  "Details2": {
      "MoreInfo": {
          "Title": "Mr"
      }
  }
}

我尝试了各种不同的方法（转换为字典并合并，附加多余的字符串{），但我似乎无法解决这个问题。有人有什么想法吗？

Answer 1

我不确定，但是我认为这行代码可能对您有帮助

NSDictionary *userInfo = @{ @"name": @"John",@"age": @34 };
NSDictionary *userMoreInfo = @{ @"Title": @"Mr", };

NSDictionary *Details = [NSDictionary dictionaryWithObject:userInfo forKey:@"Details"];
NSDictionary *MoreInfo = [NSDictionary dictionaryWithObject:userMoreInfo forKey:@"MoreInfo"];

NSMutableDictionary *finalDictThatWants = [NSMutableDictionary new];
[finalDictThatWants setObject:Details forKey:@"Details1"];
[finalDictThatWants setObject:MoreInfo forKey:@"Details2"];

Answer 2

不确定为什么要使用可变字典...

NSDictionary *details1 = @{
                           @"Details": @{
                                   @"name": @"John",
                                   @"age": @34
                                }
                           };
NSDictionary *details2 = @{
                           @"MoreInfo": @{
                                   @"Title": @"Mr"
                                }
                          };
NSData *data = [NSJSONSerialization dataWithJSONObject:@{
                                                         @"Details1": details1,
                                                         @"Details2": details2
                                                        }
                                               options:NSJSONWritingPrettyPrinted
                                                 error:nil];
NSLog(@"\n%@", [[NSString alloc] initWithData:data
                                     encoding:NSUTF8StringEncoding]);

输出

{
  "Details2" : {
    "MoreInfo" : {
      "Title" : "Mr"
    }
  },
  "Details1" : {
    "Details" : {
      "name" : "John",
      "age" : 34
    }
  }
}

使用密钥从2个JSON对象创建单个JSON字符串

2 个答案: