我正在尝试使用Java脚本开发具有旋转和缩放功能的交互式3d查看器。我成功开发了一个脚本来查看仅在一个轴(X轴)上旋转的产品,但是需要脚本示例来查看在X,Y和Z轴上获取的产品。我已附上一张显示相机放置位置的图像。
图-1显示了在单轴上拍摄图像的相机位置,这已实现,下面是代码。
<html>
<head>
<style type="text/css">
table img {
height: 250px;
width: 250px;
}
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript">
$(function () {
var arr = new Array();
var xCurrent = 0;
var currentImgPos = 0;
$("#dvImages img").each(function () {
arr.push($(this).attr("src"));
});
$("#product").attr("src", arr[0]);
$("#product").mouseleave(function () { xCurrent = 0; });
$("#product").mousemove(function (e) {
var parentOffset = $(this).parent().offset();
var relX = e.pageX - parentOffset.left;
var relY = e.pageY - parentOffset.top;
if (xCurrent > relX) {
if (relX - xCurrent <= -5) {
if (currentImgPos >= 25) {
currentImgPos = 0;
$("#product").attr("src", arr[currentImgPos]);
}
else {
currentImgPos = currentImgPos + 1;
$("#product").attr("src", arr[currentImgPos]);
}
xCurrent = relX;
}
}
else {
if (relX - xCurrent >= 5) {
if (currentImgPos <= 0) {
currentImgPos = 25;
$("#product").attr("src", arr[currentImgPos]);
}
else {
currentImgPos = currentImgPos - 1;
$("#product").attr("src", arr[currentImgPos]);
}
xCurrent = relX;
}
}
});
});
</script>
</head>
<body>
<table border="0" cellpadding="0" cellspacing="0">
<tr>
<td>
<img alt="" src="" id="product" />
</td>
</tr>
</table>
<div id="dvImages" style="display: none">
<img alt="" src="http://www.mathieusavard.info/threesixty/1.jpg" />
<img alt="" src="http://www.mathieusavard.info/threesixty/5.jpg" />
<img alt="" src="http://www.mathieusavard.info/threesixty/9.jpg" />
<img alt="" src="http://www.mathieusavard.info/threesixty/13.jpg" />
<img alt="" src="http://www.mathieusavard.info/threesixty/17.jpg" />
<img alt="" src="http://www.mathieusavard.info/threesixty/21.jpg" />
<img alt="" src="http://www.mathieusavard.info/threesixty/25.jpg" />
</div>
</body>
</html>
图-2显示在X,Y和Z轴上拍摄图像的相机位置。这部分需要示例代码