Question

我需要进行复杂的查询，以了解商店是否在一天中的特定时间营业。这是部分查询。

current_time = %Time{(time_now |> DateTime.to_time()) | microsecond: {0, 0}}
current_time_string = time_now |> DateTime.to_time() |> Time.to_string()

MyApp.StoreSchedule
  |> where(
    [rs],
      rs.from_weekday < rs.to_weekday and rs.from_weekday <= ^current_weekday and
      rs.to_weekday >= ^current_weekday and
      ((rs.open_time < rs.close_time and rs.open_time <= ^current_time and
          rs.close_time >= ^current_time) or
         (rs.close_time < rs.open_time and rs.open_time <= ^current_time and
            fragment("'23:59:59' >= ?", ^current_time_string)))
  )
  |> having([rs], count(rs.id) > 0)
  |> group_by([rs], rs.store_id)
  |> select([rs], %{store_id: rs.store_id, count: count(rs.id)})

这很好，但是我在考虑是否有某种方法可以删除fragment/2部分。我尝试了几种方法，但都没有成功。

示例1：

and '23:59:59' >= ^current_time

给出错误：

value `~T[18:35:14]` in `where` cannot be cast to type {:array, :integer} in query:

示例2：

and ^~T[23:59:59] >= ^current_time

给出错误：

** (ArgumentError) Postgrex expected a binary, got {23, 59, 59, 0}. Please make sure the value you are passing matches the definition in your table or in your query or convert the value accordingly.

比较Ecto中的静态时间

0 个答案: