如何访问熊猫单元格中的项目列表

Question

我在熊猫中有一个数据框，其中包含几列，我需要访问包含一个项目列表的一个单元格，怎么可能？ （例如，下面的示例中如何访问Match元素）

ID   Match                               
1   (word1,,,)                           
2   (word2,,,),(word1)
3   (word2,,,),(word1),(word3,,,)

Answer 1

我建议使用type Door = { id: number, rotation: number } type Handle = {| id: number |} type Entity = Handle | Door; const foo = (entity: Entity): number => { if (entity.rotation) { return entity.rotation; } else { return 2; } } 索引器，如果由于值不存在而不匹配，则返回str：

NaN

示例：

#if need slect first tuple
df['new'] = df['Match'].str[0]

#if need select second tuple and first element of tuple
df['new'] = df['Match'].str[1].str[0]

编辑：

如果值是字符串，请使用a = [[('word1','','','')], [('word2','','',''),('word1', )], [('word2','','',''),('word1', ),('word3','','','')]] df = pd.DataFrame({'ID':[1,2,3], 'Match':a}) df['new1'] = df['Match'].str[0] df['new2'] = df['Match'].str[1].str[0] print (df) ID Match new1 new2 0 1 [(word1, , , )] (word1, , , ) NaN 1 2 [(word2, , , ), (word1,)] (word2, , , ) word1 2 3 [(word2, , , ), (word1,), (word3, , , )] (word2, , , ) word1 ：

ast.literal_eval