Question

我正在尝试对诺言进行单元测试。这是代码：

it('it should return some 10 user data with ok status code when called with url ', (done) => {
    return user.getUsers('https://jsonplaceholder.typicode.com/users')
    .then((response) => {
        console.log('me here')
        assert.equal(JSON.parse(response).length, 10)
    })
    .catch((err)=>{
        console.log('me in error')
        assert.fail('err')
    })
})

上面的代码在运行时会引发以下错误： Error: Timeout of 2000ms exceeded. For async tests and hooks, ensure "done()" is called; if returning a Promise, ensure it resolves. (C:\Users\ajay\jay-workspace\UniTestModule\test\user.test.js)

Answer 1

done没有被调用，这导致测试超时。

摩卡咖啡本机支持诺言。有承诺的情况下不应使用done；相反，应返回承诺：

it('it should return some 10 user data with ok status code when called with url ', () => {
    return user.getUsers('https://jsonplaceholder.typicode.com/users')
    .then((response) => {
        console.log('me here')
        assert.equal(JSON.parse(response).length, 10)
    });
})

被拒绝的承诺将无法通过测试，也不需要assert.fail。

Answer 2

使用异步测试时，您应该调用done（）回调（有关详细信息，请检查https://mochajs.org/#asynchronous-code）。

it('it should return some 10 user data with ok status code when called with url ', (done) => {
user.getUsers('https://jsonplaceholder.typicode.com/users')
.then((response) => {
    console.log('me here')
    assert.equal(JSON.parse(response).length, 10);
    done();
})
.catch((err)=>{
    console.log('me in error')
    assert.fail('err');
    done(err);
})

Answer 3

您应该使用--timeout钩子并像./node_module/.bin/mocha test/ --timeout=5000那样增加毫秒数或者，您可以在测试用例正文中添加this.timeout(5000)

it('it should return some 10 user data with ok status code when called with url ', (done) => {
user.getUsers('https://jsonplaceholder.typicode.com/users')
.then((response) => {
    console.log('me here')
    assert.equal(JSON.parse(response).length, 10);
    this.timeout(5000);
    setTimeout(done, 3000);
})

https://mochajs.org/#test-level

Mocha单元测试Promise引发错误

3 个答案: