Question

我有一个基本的交易表，下面的查询为我提供了最近一个月所有交易的计数：

Select count(status)
FROM TX 
WHERE Date_Reported >= DATEADD(mm,DATEDIFF(mm,0,GETDATE())-1,0)
AND Date_Reported < DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)

我想要的是将该值与前一个月进行比较，并找到增加或减少的百分比。

例如，我们在7月，上述查询将为我提供6月的交易计数（即100）。我需要计数整个5月（2个月前），并找到％差异。因此，如果5月为50，6月为100，则查询应返回100％

有什么想法吗？

Answer 1

使用窗口功能：

with cte as(
select year(Date_reported) as [Year], month(Date_reported) as [Month], count(Status) as [StatusCount]
FROM TX
group by year(Date_reported), month(Date_reported)
)
Select [Year], [Month], [StatusCount]
    , 100.0*([StatusCount] - lag([StatusCount]) OVER (ORDER BY [Year], [Month]))/lag([StatusCount]) OVER (ORDER BY [Year], [Month]) as [PercentageDiff]
from cte

Answer 2

给出以下方法，应该可以正常工作，但是不要认为这是最佳解决方案：

declare @lastMonth int = 
  (Select count(status)
  FROM TX 
  WHERE Date_Reported >= DATEADD(mm,DATEDIFF(mm,0,GETDATE())-1,0)
    AND Date_Reported < DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0))

declare @beforeLastMonth int = 
  (Select count(status)
  FROM TX 
  WHERE Date_Reported >= DATEADD(mm,DATEDIFF(mm,0,GETDATE())-2,0)
    AND Date_Reported < DATEADD(mm,DATEDIFF(mm,0,GETDATE())-1,0))


declare @result int = (@lastMonth - @beforeLastMonth) * 100 / @beforeLastMonth

Answer 3

如果仅需要2个月，则可以尝试以下查询。否则，您可以添加序列（1,2,3,4,5 ...），然后使用它代替固定整数：

CREATE TABLE tx
(
    status        CHAR(1)
  , date_reported DATE
);

INSERT INTO tx
VALUES ('A', '20180709')
     , ('B', '20180708')
     , ('A', '20180701')
     , ('B', '20180609')
     , ('A', '20180608')
     , ('A', '20180509')
     , ('B', '20180501');

  SELECT       SUM(months.is_last_month)
           , SUM(months.is_last2_month)
           , (SUM(months.is_last_month) - SUM(months.is_last2_month)) * 100 / SUM(months.is_last2_month)
  FROM       tx                                AS t
 OUTER APPLY (   SELECT CASE WHEN Date_Reported >= DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) - 1, 0)
                             AND  Date_Reported < DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0) THEN 1
                        END AS is_last_month
                      , CASE WHEN Date_Reported >= DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) - 2, 0)
                              AND Date_Reported < DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) - 1, 0) THEN 1
                        END AS is_last2_month) AS months
 WHERE       t.date_reported >= DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) - 2, 0)
   AND       t.date_reported       < DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0);

Answer 4

尝试一下

with CurMon as (
  Select count(status) CurStat
  FROM TX 
  WHERE Date_Reported >= DATEADD(mm,DATEDIFF(mm,0,GETDATE())-1,0)
  AND Date_Reported < DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)
)
,
 PreMon as (
  Select count(status) PreStat
  FROM TX 
  WHERE Date_Reported >= DATEADD(mm,DATEDIFF(mm,0,GETDATE())-2,0)
  AND Date_Reported < DATEADD(mm,DATEDIFF(mm,0,GETDATE())-1,0)
)

select  case when PreStat>0 then 100*(CurStat-  PreStat)/PreStat else 0 end as pct
from CurMon  join PreMon on 1=1

Answer 5

我建议您在pl / sql函数中执行此操作，因为它更容易：

        if (!empty($array2)){
          foreach ($array2 as $key => $value) { ?>
              <div class="panel panel-default center-block developerinfo">
                  <div class="panel-body">
                      <div class=row>
                          <div class="col-md-12">
                              <h2 style="color:orangered" class="text-center">SIP</h2>
                              <img alt="" class="center-block"style="width:20%;"src="../../css/collecting/logo.png">
                              <h2 class="text-center"><?php echo $value['name_dvp']; ?></h2>
                              <h3 class="text-center">(<?php echo $value['region_dvp']; ?>)</h3>
                              <h3 class="text-center">D<?php echo $value['id_dvp']; ?></h3>
                              <h2 style="color:orangered" class="text-center"><?php echo $value['maintenancelocation_dvp']; ?></h2>

                              <img alt="" class=" center-block developerlocationselection check cursor selection-button" src="../../css/collecting/route-select.png" name="<?php echo $value['name_dvp']; ?>" region = "(<?php echo $value['region_dvp']; ?>)" id="D<?php echo $value['id_dvp']; ?>" location="<?php echo $value['maintenancelocation_dvp']; ?>" routeid="<?php echo $value['idroute']; ?>"sipid="<?php echo $value['id_sip']; ?>">

                              <ul id="developercheckbox">
                              <input type="checkbox" class="developernames" name="developernames"  style="display:none;">
                              </ul>
                          </div>
                      </div>
                  </div>
              </div>
              <?php
              }
          }

没有表很难仅在一个查询中尝试解决方案

两个月前的数据

5 个答案: