使用Python,Selenium和Webdriver,需要随后使用网页上的find_element_by_xpath()方法单击文本找到的元素。
(公司内部网页,所以不能提供网址)
通过xpath是最好的方法,但是我想找到并单击多个文本。
它可以单独工作,如:
driver.find_element_by_xpath("//*[contains(text(), 'Kate')]").click()
对于多个,这是我尝试的:
name_list = ["Kate", "David"]
for name in name_list:
xpath = "//*[contains(text(), '"
xpath += str(name)
xpath += "')]"
print xpath
driver.find_element_by_xpath(xpath).click()
time.sleep(5)
print xpath的输出看起来不错,但是硒表示:
common.exceptions.NoSuchElementException
答案 0 :(得分:2)
您可以如下简化代码:
for name in name_list:
driver.find_element_by_xpath("//*[contains(text(), '%s')]" % name).click()
或
for name in name_list:
try:
driver.find_element_by_xpath("//*[contains(text(), '{}')]".format(name)).click()
except:
print("Element with name '%s' is not found" % name)
答案 1 :(得分:2)
使用字符串格式。将占位符放入xpath字符串中,并用变量值填充:
name_list = ["Kate", "David"]
for name in name_list:
xpath = "//*[contains(text(),'{}')]".format(name)
driver.find_element_by_xpath(xpath).click()
答案 2 :(得分:1)
尝试一下:
name_list = ["Kate", "David"]
for name in name_list:
xpath = "//*[contains(text(), '" + str(name) + "')]" # simplified
print xpath
list = driver.find_elements_by_xpath(xpath) # locate all elements by xpath
if len(list) > 0: # if list is not empty, click on element
list[0].click() # click on the first element in the list
time.sleep(5)
这将防止抛出
common.exceptions.NoSuchElementException
注意:还请确保您使用正确的xPath。