Question

我有2个表RD（休息日）和用于插入值的课程。看起来像这样。我的第二张桌子看起来像这样

Sun Mon Tue Wed Thu Fri Sat         Sun Mon Tue Wed Thu Fri Sat          

        RD                           13   13  13  13  13 13

如何在第二张桌子上验证。如果星期一有RD，则第二个表上的13为0，表示没有值，因为星期一是教师的RD。因为我目前正在做一个教师轮班制。这是我的插入查询

include('../dist/includes/dbcon.php');
$cewnd = $_POST['cewnd'];
$cewd = $_POST['cewd'];
$cewd = $_POST['cewd'];
$ckwd = $_POST['ckwd'];
$ckwd = $_POST['ckwd'];
$ckwd = $_POST['ckwd'];
$ckwnd = $_POST['ckwnd'];


$query=mysqli_query($con,"select * from t_lessons")or die(mysqli_error());
$count=($query);
if ($count)
{
    echo "<script>document.location='test.php'</script>";
}else{
    mysqli_query($con,"INSERT INTO t_lessons(Sun,Mon,Tue,Wed,Thu,Fri,Sat) VALUES('$cewnd','$cewd','$cewd','$cewd','$cewd','$cewd','cewnd ')")or 
        die(mysqli_error($con));
    echo "<script type='text/javascript'>
        alert('Successfuly added new Lessons');</script>";
    echo "<script>document.location='test.php'</script>";
}

 This is the code of my modal.

    <table border="2" style="float:top; width=10%">
   <thead>
   <tr>
    <th bgcolor="FFFF00">CE Order</th>&nbsp;&nbsp;

   </thead>
   </table>

  <br><table border="2" style="float:top; width=10%">
  <thead>
  <tr>
   <th>    Day 1- 15<br>
    <input type="text"  name="1sthalf" value="3,500"  required>
    <br>Day 16-<br>
       <input type="text"  name="2ndhalf" value="3,500"  required>
   </th>      </div><!-- /.form group -->


  </thead>
   </table>
    <table border="2" style="float:top; width=10%">
   <thead>
    <tr>
      <th bgcolor="FFFF00">CE Slots</th>&nbsp;&nbsp;

     </thead>

    <table border="2" style="float:top; width=10%"><br>
    <thead>
      <tr>
    <th>    CE Weekday<br>
      <input type="text"  name="cewd" placeholder="0">
      <br>CE Weekend<br>
         <input type="text"  name="cewnd" placeholder="0">
   <br>    CK Weekday<br>
      <input type="text"  name="ckwd" placeholder="0">
      <br>CK Weekend<br>
         <input type="text"  name="ckwnd" placeholder="0">
      <br> <button class="btn btn-lg btn-primary btn-block signup-btn" 
     type="submit" name="add" id="add">
           Add
         </button>
    </th>
   </div><!-- /.form group -->


      </thead>
       </table>
   </table>

Answer 1

一段时间后，我成功地设法验证了插入查询。请设置相同的列名（如果两个表上的列名不同）。

<?php

$host="localhost";
$username="root";
$password="";
$database= "mydemo";

// Opens a connection to a mySQL server
$connection = mysqli_connect($host, $username, $password);

if (!$connection) {
  die("Not connected : ".mysqli_error());
}
// Set the active mySQL database
$dbselected = mysqli_select_db($connection,$database);

if (!$dbselected) {
  die ("Can\'t use db : " . mysqli_error());
}

function build_sql_insert($table, $data,$con) {
    $key = array_keys($data);
    $val = array_values($data);
    $sql = "INSERT INTO $table (" . implode(', ', $key) . ") "
         . "VALUES ('" . implode("', '", $val) . "')";
    $res = mysqli_query($con, $sql) or die(mysqli_error($con));
    return($res);
}

// Here you select data from the table rd so you get which columns has "RD" value 
$result=mysqli_query($connection,"select sun,mon,tue,wed,thur,fri,sat from rd") or die(mysqli_error());
$arr1 = mysqli_fetch_assoc($result);
// In below there is some modification perform so it fit on your need
foreach($arr1 as $k=>$v){
    if(strlen($v)){
        $temp[$k] = 0;
    }
}

// This is your array which is need to be manage by you. Here i write some static values but you have to manage it.
$arr2 = array(
    'sun'=> 10, 
    'mon'=> 14,
    'tue'=> 14,
    'wed'=> 14,
    'thur'=> 14,
    'fri'=> 14,
    'sat'=> 10
);

$finalarr = array_merge($arr2,$temp);
//Here is $connection has the connection object. 'lesson' is the table name and $finalarr is the array which we made to insert
$resi = build_sql_insert('lesson', $finalarr,$connection);
if($resi ==1){
    echo "<script type='text/javascript'>
        alert('Successfuly added new Lessons');</script>";
    echo "<script>document.location='test.php'</script>";
}

?>

加油！您的问题已经解决。

有条件插入mysql数据

1 个答案: