Question

所以我有一张名为Vouchers的表：

ID_ENTITY -> Unique Key
ID_VOUCHER 
VOUCHER_CODE
AMNT_VOUCHER_DENOM
ID_VOUCHER_STATUS
DAT_EXPIRE_DATE

我有一个计数查询：

select count(*),AMNT_VOUCHER_DENOM,ID_VOUCHER 
from CUS_VOUCHERS
where ID_VOUCHER_STATUS = 0 
and ID_VOUCHER = 1 
and trunc(DAT_EXPIRE_DATE) >= trunc(sysdate)
group by AMNT_VOUCHER_DENOM,ID_VOUCHER;

结果：

-----------------------------------------
COUNT | AMNT_VOUCHER_DENOM |  ID_VOUCHER
1     |100000              |1
      |                    |

预期结果：

----------------------------------------
COUNT | AMNT_VOUCHER_DENOM  | ID_VOUCHER
1     | 100000              |1
0     |150000               |1
0     |200000               |1

实际上我有很多AMNT_VOUCHER_DENOM和ID_VOUCHER = 1，但还有ID_VOUCHER_STATUS != 0。

我该怎么办？

Answer 1

删除ID_VOUCHER_STATUS上的过滤器，并使用case语句对感兴趣的项目进行计数

select count(case when ID_VOUCHER_STATUS = 0 then 1 end) as no_of_sts_0
       , AMNT_VOUCHER_DENOM,ID_VOUCHER 
from CUS_VOUCHERS
where ID_VOUCHER = 1 
and trunc(DAT_EXPIRE_DATE) >= trunc(sysdate)
group by AMNT_VOUCHER_DENOM,ID_VOUCHER;

这里是a SQL Fiddle demo

Answer 2

WHERE ID_VOUCHER_STATUS = 0 and ID_VOUCHER = 1将排除所有AMNT_VOUCHER_DENOM和ID_VOUCHER_STATUS != 0。

因此您要执行：

select count(*),AMNT_VOUCHER_DENOM,ID_VOUCHER from CUS_VOUCHERS
where ID_VOUCHER = 1 and trunc(DAT_EXPIRE_DATE) >= trunc(sysdate)
group by AMNT_VOUCHER_DENOM,ID_VOUCHER;`

从单个表在Oracle中返回0，带计数的值

2 个答案: