Question

因此，我正在为汽车经销商编写程序，这是我班的最后一个项目。这时候我要说大约完成了75％，但是在弄清楚如何更新数组列表中的用户输入时遇到了麻烦。因此，每个阵列列表插槽均包含汽车的年份，品牌，型号，颜色和行驶里程。我可以添加新车，可以移除车，然后退出程序。我已经尝试了很多事情，读了许多论文，博客，论坛和我的课堂书籍，但是它总是随着程序员的输入而更新。

package carDealer;

import java.util.ArrayList;
import java.util.Scanner;

public class VehicleInformation {

public static void main(String [] args) {

    Scanner scnr = new Scanner(System.in);
    ArrayList<VehicleInventory> car = new ArrayList<VehicleInventory>();
    String userInput = "-";

    while (!userInput.equals("q")) {
        System.out.println("Commands: 'a' to add, 'd' to delete, 'e' to edit, 'q' to quit");
        userInput = scnr.next();

        if (userInput.equals("a")) {
            System.out.println("Year: ");
            int year = scnr.nextInt();
            System.out.println("Make: ");
            String make = scnr.next();
            System.out.println("Model: ");
            String model = scnr.next();
            System.out.println("Color: ");
            String color = scnr.next();
            System.out.println("Mileage: ");
            int mileage = scnr.nextInt();

            VehicleInventory userCar = new VehicleInventory();      
            userCar.setMake(make);
            userCar.setModel(model);
            userCar.setYear(year);
            userCar.setColor(color);
            userCar.setMileage(mileage);
            userCar.print();

            addCar(car, userCar);
        }

        if (userInput.equals("d")) {
            for (int i = 0; i < car.size(); ++i) {
                System.out.print((i + 1) + " ");
                car.get(i).print();
            }

            System.out.println("List number: ");
            int userNum = scnr.nextInt();
            car.remove(userNum - 1);
            System.out.println("count: " + car.size());
        }

        if (userInput.equals("e")) {
            for (int i = 0; i < car.size(); ++i) {
                System.out.print((i + 1) + " ");
                car.get(i).print();

            }

            System.out.println("List number: ");
            int userNum = scnr.nextInt();
            car.get(userNum - 1);

Answer 1

您可以做一个循环来查找用户想要更新的汽车模型（可以是任何其他属性），一旦找到要更新的模型，其值即为所需值：

String vehicleToLookUp = "golf"; // This will be received by user input
String vehicleNewName = "golf gti"; // This will be received by user input
for( int i = 0; i < car.size(); i++){
    if(vehicleToLookUp.getModel().equals(car.get(i)){
        car.get(i).setSomeAttribute(...); // Set the desired attribute here
    }
}

或者如果您想替换整个对象...

String vehicleToLookUp = "golf"; // This will be received by user input
VehicleInventory newVehicle = new VehicleInventory(); // You will set the attributes by user input
for( int i = 0; i < car.size(); i++){
    if(vehicleToLookUp.getModel().equals(car.get(i)){
        car.set(i, newVehicle ); // Create your object and pass it here
    }
}

此外，您可以使用if甚至使用if/else if代替所有的switch/case，以获得更好的性能/可读性（请考虑，即使您的逻辑对于第一个{{1 }}，它将检查您创建的所有其他if，浪费时间和处理能力。

如何更新数组列表中的用户输入？

1 个答案: