Question

我在将单列值拆分为多个列值时遇到问题。

例如：

Name
------------
abcd efgh
ijk lmn opq
asd j. asdjja
asb (asdfas) asd
asd

我需要这样的输出：

first_name             last_name
----------------------------------
abcd                     efgh
ijk                      opq
asd                      asdjja
asb                      asd
asd                      null

可以省略中间名（不需要中间名）列已经创建，需要插入单个Name列中的数据。

Answer 1

你的方法不会正确处理很多名字，但是......

SELECT CASE
         WHEN name LIKE '% %' THEN LEFT(name, Charindex(' ', name) - 1)
         ELSE name
       END,
       CASE
         WHEN name LIKE '% %' THEN RIGHT(name, Charindex(' ', Reverse(name)) - 1)
       END
FROM   YourTable

Answer 2

马丁的另一种选择

select LEFT(name, CHARINDEX(' ', name + ' ') -1),
       STUFF(name, 1, Len(Name) +1- CHARINDEX(' ',Reverse(name)), '')
from somenames

样本表

create table somenames (Name varchar(100))
insert somenames select 'abcd efgh'
insert somenames select 'ijk lmn opq'
insert somenames select 'asd j. asdjja'
insert somenames select 'asb (asdfas) asd'
insert somenames select 'asd'
insert somenames select ''
insert somenames select null

Answer 3

您需要的是分割用户定义的功能。有了它，解决方案看起来像

With SplitValues As
    (
    Select T.Name, Z.Position, Z.Value
        , Row_Number() Over ( Partition By T.Name Order By Z.Position ) As Num
    From Table As T
        Cross Apply dbo.udf_Split( T.Name, ' ' ) As Z
    )
Select Name
    , FirstName.Value
    , Case When ThirdName Is Null Then SecondName Else ThirdName End As LastName
From SplitValues As FirstName
    Left Join SplitValues As SecondName
        On S2.Name = S1.Name
            And S2.Num = 2
    Left Join SplitValues As ThirdName
        On S2.Name = S1.Name
            And S2.Num = 3
Where FirstName.Num = 1

这是一个示例拆分功能：

Create Function [dbo].[udf_Split]
(   
    @DelimitedList nvarchar(max)
    , @Delimiter nvarchar(2) = ','
)
RETURNS TABLE 
AS
RETURN 
    (
    With CorrectedList As
        (
        Select Case When Left(@DelimitedList, Len(@Delimiter)) <> @Delimiter Then @Delimiter Else '' End
            + @DelimitedList
            + Case When Right(@DelimitedList, Len(@Delimiter)) <> @Delimiter Then @Delimiter Else '' End
            As List
            , Len(@Delimiter) As DelimiterLen
        )
        , Numbers As 
        (
        Select TOP( Coalesce(DataLength(@DelimitedList)/2,0) ) Row_Number() Over ( Order By c1.object_id ) As Value
        From sys.columns As c1
            Cross Join sys.columns As c2
        )
    Select CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen As Position
        , Substring (
                    CL.List
                    , CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen     
                    , CharIndex(@Delimiter, CL.list, N.Value + 1)                           
                        - ( CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen ) 
                    ) As Value
    From CorrectedList As CL
        Cross Join Numbers As N
    Where N.Value <= DataLength(CL.List) / 2
        And Substring(CL.List, N.Value, CL.DelimiterLen) = @Delimiter
    )

Answer 4

;WITH Split_Names (Name, xmlname)
AS
(
    SELECT 
    Name,
    CONVERT(XML,'<Names><name>'  
    + REPLACE(Name,' ', '</name><name>') + '</name></Names>') AS xmlname
      FROM somenames
)

 SELECT       
 xmlname.value('/Names[1]/name[1]','varchar(100)') AS first_name,    
 xmlname.value('/Names[1]/name[2]','varchar(100)') AS last_name
 FROM Split_Names

并查看以下链接以供参考

http://jahaines.blogspot.in/2009/06/converting-delimited-string-of-values.html

Answer 5

我最近使用过它：

select 
substring(name,1,charindex(' ',name)-1) as Col1,
substring(name,charindex(' ',name)+1,len(name)) as Col2 
from TableName

Answer 6

以下是我在SQLite数据库上执行此操作的方法：

SELECT SUBSTR(name, 1,INSTR(name, " ")-1) as Firstname, SUBSTR(name, INSTR(name," ")+1, LENGTH(name)) as Lastname FROM YourTable;

希望它有所帮助。

Answer 7

SELECT
   SUBSTRING_INDEX(SUBSTRING_INDEX(rent, ' ', 1), ' ', -1) AS currency,
   SUBSTRING_INDEX(SUBSTRING_INDEX(rent, ' ', 3), ' ', -1) AS rent
FROM tolets

如何将单个列值拆分为多个列值？

7 个答案: