Question

我正在尝试创建一个列表，其中包含在双引号中找到的所有字符串，到目前为止，我已经知道了。

matches = ['8 "app/Http/Controllers/Controller.php" line 1', '9 "app/Http/Controllers/PostController.php" line 1']

if len(matches) > 1:
    for match in matches:
        matches = re.findall(r'\"(.+?)\"', match)
        print(matches[0])

它输出此

app/Http/Controllers/Controller.php
app/Http/Controllers/PostController.php

我想将这些字符串变成一个列表，这样看起来

['app/Http/Controllers/Controller.php','app/Http/Controllers/PostController.php']

它也应该是动态的，因为双引号内可以有两个以上的字符串。

这怎么办？

Answer 1

您可以将print语句用append替换为循环之前初始化的列表。

import re
matches = ['8 "app/Http/Controllers/Controller.php" line 1', '9 "app/Http/Controllers/PostController.php" line 1']

output = []
if len(matches) > 1:
    for match in matches:
        matches = re.findall(r'\"(.+?)\"', match)
        output.append(matches[0])

print(output)

这将输出：

['app/Http/Controllers/Controller.php', 'app/Http/Controllers/PostController.php']

Answer 2

您可以使用list comprehension来更简洁地生成列表。

在python中，列表推导允许`[x for x in（1,4,3,2）]格式。

所以这将导致这段代码。

import re
matches = ['8 "app/Http/Controllers/Controller.php" line 1', '9 "app/Http/Controllers/PostController.php" line 1']

results = [re.findall(r'\"(.+?)\"', match)[0] for match in matches]

结果变量将为：

['app/Http/Controllers/Controller.php', 'app/Http/Controllers/PostController.php']

内部的隐蔽字符串用于循环到列表中

2 个答案: