Question

给出一个Product

@Entity
public class Product {

    private Long id;
    private List<Review> reviews;

    public Product() {}

    @Id
    @GeneratedValue
    public Long getId() {
        return this.id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    @ElementCollection
    public List<Review> getReviews() {
        return reviews;
    }

    public void setReviews(List<Review> reviews) {
        this.reviews = reviews;
    }

    // equals() and hashCode() omitted for brevity
}

还有一个可嵌入的Review

@Embeddable
public class Review {

    private Customer author;
    private String title;
    private String comment;

    public Review() {}

    @ManyToOne(optional = false)
    @Column(unique = true)
    public Customer getAuthor() {
        return author;
    }

    public void setAuthor(Customer author) {
        this.author = author;
    }

    @Column(nullable = false)
    public String getTitle() {
        return title;
    }

    public void setTitle(String title) {
        this.title = title;
    }

    @Column(nullable = false, length = 2000)
    public String getComment() {
        return comment;
    }

    public void setComment(String comment) {
        this.comment = comment;
    }
}

如何为Review的作者设置唯一约束。换句话说：我想确定的是，对于给定的产品，每个评论都有不同的作者。

我可以使用@NaturalId吗？我是否使用@Column(unique = true)？我已经找到了a similar question on StackOverflow，但就我而言，它是Embeddable的列表，而不仅仅是成员，所以我猜想这种方法行不通。

非常感谢！

Answer 1

如果您要谈论的是在模式生成期间添加唯一的数据库索引，则可以执行以下操作：

@ElementCollection
@CollectionTable(name = "product_reviews", 
       uniqueConstraints = {@UnqiqueConstraint(columnNames={"product_id", "author_id"})})
public List<Review> getReviews() {
    return reviews;
}

休眠：可嵌入对象列表的唯一约束（@ElementCollection）

1 个答案: