我正在尝试编写一个小的Java应用程序,该应用程序返回员工的详细信息。这是我的员工班。
public class Employees {
private int id;
private Date dateofBirth;
private String firstName;
private String lastName;
private enum gender{
M, F;
}
private gender employeeGender;
private Date dateHired;
public String getEmployeeGender() {
return this.employeeGender.name();
}
public void setEmployeeGender(String employeeGender) {
this.employeeGender = gender.valueOf(employeeGender);
}
/*Getters, setters omitted*/
这是我的DAO课
public class EmployeeDao {
final String TABLE_EMPLOYEES = "employees";
final String COLUMN_EMPLOYEES_ID = "emp_no";
final String COLUMN_EMPLOYEES_DOB = "birth_date";
final String COLUMN_EMPLOYEES_FIRST_NAME = "first_name";
final String COLUMN_EMPLOYEES_LAST_NAME = "last_name";
final String COLUMN_EMPLOYEES_GENDER = "gender";
final String COLUMN_EMPLOYEES_HIRE_DATE = "hire_date";
final String QUERY_EMPLOYEES = "SELECT * FROM " + TABLE_EMPLOYEES + " WHERE " + COLUMN_EMPLOYEES_ID + " = ?";
public Employees getEmployeeDetails(int employeeId) {
Employees employee = new Employees();
try (DbConnection dbConnection = new DbConnection();
Connection databaseConnection = dbConnection.getConn();
PreparedStatement selectFromEmployees = databaseConnection.prepareStatement(QUERY_EMPLOYEES)) {
selectFromEmployees.setInt(1, employeeId);
try (ResultSet result = selectFromEmployees.executeQuery()) {
if (result.next() == false) {
System.out.println("Empty Resultset");
}
while (result.next()) {
employee.setId(result.getInt(COLUMN_EMPLOYEES_ID));
employee.setFirstName(result.getString(COLUMN_EMPLOYEES_FIRST_NAME));
employee.setLastName(result.getString(COLUMN_EMPLOYEES_LAST_NAME));
employee.setDateofBirth(result.getDate(COLUMN_EMPLOYEES_DOB));
employee.setEmployeeGender(result.getString(COLUMN_EMPLOYEES_GENDER));
employee.setDateHired(result.getDate(COLUMN_EMPLOYEES_HIRE_DATE));
}
}
} catch (Exception e) {
e.printStackTrace();
}
return employee;
}
}
但是当我尝试以这种主要方法运行应用程序时,我得到的输出为空值。
public static void main(String[] args) {
EmployeeDao employeeDao = new EmployeeDao();
Employees employees = employeeDao.getEmployeeDetails(39256);
System.out.println(employees.getId() + " \n" + employees.getFirstName() + " \n" + employees.getLastName() + " \n" + employees.getDateofBirth() + " \n" + employees.getDateHired());
}
答案 0 :(得分:4)
您不应两次调用next
,因为它将再次使光标向前移动。试试这个:
if (result.next() == false) {
System.out.println("Empty Resultset");
} else {
employee.setId(result.getInt(COLUMN_EMPLOYEES_ID));
employee.setFirstName(result.getString(COLUMN_EMPLOYEES_FIRST_NAME));
employee.setLastName(result.getString(COLUMN_EMPLOYEES_LAST_NAME));
employee.setDateofBirth(result.getDate(COLUMN_EMPLOYEES_DOB));
employee.setEmployeeGender(result.getString(COLUMN_EMPLOYEES_GENDER));
employee.setDateHired(result.getDate(COLUMN_EMPLOYEES_HIRE_DATE));
}
答案 1 :(得分:2)
调用ResultSet#next
会将光标向前移动一行,因此您的if
条件将丢失第一行。由于您知道查询最多可以返回一行,因此根本不需要while
循环,
public Employees getEmployeeDetails(int employeeId) throws SQLException {
Employees employee = null;
try (DbConnection dbConnection = new DbConnection();
Connection databaseConnection = dbConnection.getConn();
PreparedStatement selectFromEmployees =
databaseConnection.prepareStatement(QUERY_EMPLOYEES)) {
selectFromEmployees.setInt(1, employeeId);
try (ResultSet result = selectFromEmployees.executeQuery()) {
if (result.next()) {
employee = new Employees();
employee.setId(result.getInt(COLUMN_EMPLOYEES_ID));
employee.setFirstName(result.getString(COLUMN_EMPLOYEES_FIRST_NAME));
employee.setLastName(result.getString(COLUMN_EMPLOYEES_LAST_NAME));
employee.setDateofBirth(result.getDate(COLUMN_EMPLOYEES_DOB));
employee.setEmployeeGender(result.getString(COLUMN_EMPLOYEES_GENDER));
employee.setDateHired(result.getDate(COLUMN_EMPLOYEES_HIRE_DATE));
}
}
}
return employee;
}
答案 2 :(得分:2)
无需添加额外的<object>
比较。
result.next()
while仅在有任何行时执行。
在用于检查列表中是否包含值之前,请检查所生成列表的大小。