我有两个相互关联的表(如屏幕截图所示):
现在,我从表格zerts中进行选择,并希望将所有zerts放在列表中。现在,我想通过用户标识获取用户名。如何访问已连接的数据?
$sql = "SELECT * FROM zerts ORDER BY created";
$result = mysqli_query($conn, $sql);
while($row = mysqli_fetch_assoc($result)) {
echo "<tr><td>" . $row["id"] . "</td><td>" . $row["userid"] . "</td><td>" . $row["username"] . "</td></tr>";
}
为什么无法通过用户ID获取用户名?我在用户名字段中得到空白输出。
答案 0 :(得分:0)
您需要为此创建联接才能访问其他表的用户名。
#include <iostream>
#include "Piso1.h"
using namespace std;
Piso1::Piso1(){
};
int Piso1::Draw(RenderWindow &window, Event &evento)
{
srand(time(nullptr));
Soundtrack.openFromFile("../Scenes/Piso1/Sounds/Neon District.wav");
Soundtrack.setLoop(true);
Soundtrack.play();
Texture BGTexture;
BGTexture.loadFromFile("../Scenes/Piso1/Graphics/piso1background.png");
Sprite Background;
Background.setTexture(BGTexture);
Background.setScale(8,7.5);
Background.setPosition(BackX,BackY);
Texture FGTexture;
FGTexture.loadFromFile("../Scenes/Piso1/Graphics/piso1foreground.png");
Sprite Foreground;
Foreground.setTexture(FGTexture);
Foreground.setScale(8,7.5);
Foreground.setPosition(BackX,BackY);
Texture ProtaTextura;
ProtaTextura.loadFromFile("../Scenes/Piso1/Graphics/pSprite.png");
IntRect SpriteBx(0,0,34,47);
Sprite Protagonista(ProtaTextura,SpriteBx);
Protagonista.setPosition((window.getSize().x)/2.35,(window.getSize().y)/3);
Protagonista.setScale(3,3);
while (window.isOpen()) {
while (window.pollEvent(evento)) {
switch (evento.type) {
case Event::Closed:
window.close();
break;
case Event::KeyPressed:
EncounterValue = rand()%1000;
if(EncounterValue > 5){
if(evento.key.code == Keyboard::Down) {
BackY -= 10;
Background.move(0,-10);
Foreground.move(0,-10);
//this is my failed attempt
if(Protagonista.getLocalBounds().intersects(Foreground.getLocalBounds()))
{
Collision.openFromFile("../Scenes/Piso1/Sounds/oof.ogg");
Collision.play();
BackY += 10;
Background.move(0, 10);
Foreground.move(0, 10);
}
if(clock1.getElapsedTime().asMilliseconds()>64){
SpriteBx.top = 0;
if (SpriteBx.left == 0)
SpriteBx.left = 34;
else if (SpriteBx.left==34)
SpriteBx.left= 68;
else if (SpriteBx.left== 68)
SpriteBx.left= 102;
else
SpriteBx.left=0;
Protagonista.setTextureRect(SpriteBx);
clock1.restart();
}
break;
}
else if (evento.key.code == Keyboard::Up) {
BackY += 10;
Background.move(0,10);
Foreground.move(0,10);
if (clock1.getElapsedTime().asMilliseconds()>64)
{
SpriteBx.top = 152;
if (SpriteBx.left == 0)
SpriteBx.left = 34;
else if (SpriteBx.left==34)
SpriteBx.left= 68;
else if (SpriteBx.left== 68)
SpriteBx.left= 102;
else
SpriteBx.left=0;
Protagonista.setTextureRect(SpriteBx);
clock1.restart();
}
break;
}
else if(evento.key.code == Keyboard::Left) {
BackX += 10;
Background.move(10,0);
Foreground.move(10,0);
if (clock1.getElapsedTime().asMilliseconds()>64)
{
SpriteBx.top = 53;
if (SpriteBx.left == 0)
SpriteBx.left = 34;
else if (SpriteBx.left==34)
SpriteBx.left= 68;
else if (SpriteBx.left== 68)
SpriteBx.left= 102;
else
SpriteBx.left=0;
Protagonista.setTextureRect(SpriteBx);
clock1.restart();
}
break;
}
else if(evento.key.code == Keyboard::Right){
BackX -= 10;
Background.move(-10,0);
Foreground.move(-10,0);
if (clock1.getElapsedTime().asMilliseconds()>64)
{
SpriteBx.top = 104;
if (SpriteBx.left == 0)
SpriteBx.left = 34;
else if (SpriteBx.left==34)
SpriteBx.left= 68;
else if (SpriteBx.left== 68)
SpriteBx.left= 102;
else
SpriteBx.left=0;
Protagonista.setTextureRect(SpriteBx);
clock1.restart();
}
break;
}
else if(evento.key.code == Keyboard::C){
Soundtrack.stop();
return 1;
}
}
else{
Soundtrack.stop();
return 0;
}
}
window.clear();
window.draw(Foreground);
window.draw(Background);
window.draw(Protagonista);
window.display();
}
}
}
答案 1 :(得分:0)
请更新您的查询,其余代码相同。
$sql = "SELECT zerts.*,users.username FROM zerts
LEFT JOIN users ON (zerts.userid = users.id) ORDER BY zerts.created";
希望获得帮助。