Question

我是Codeigniter的新手。我试图将Ajax查询表单用于我的产品详细信息视图，并希望将表单详细信息保存到详细信息到db表（查询）中。但是每次我收到错误消息。

Failed to load resource: the server responded with a status of 404 (Not Found) - send_inq

请告诉我一种解决方法。

这些是我的Controller，Ajax和视图编码

控制器

        public function send_inq(){
                $data = array(
                    'ref_id' => $this->input->post('ref_prod'),
                    'customer_name' => $this->input->post('customer_name'),
                    'customer_email' => $this->input->post('customer_email')
                );
                $this->db->insert('inquiries', $data);
        }

Ajax

<!--Ajax Submit-->
        <script type="text/javascript">
            $(document).ready(function(){
                $("#send-inquiry").submit(function(e){
                    e.preventDefault();
                    var ref_prod = $("#ref_prod").val();
                    var customer_name = $("#customer_name").val();
                    var customer_email = $("#customer_email").val();
                    $.ajax({
                        type: "POST",
                        url: '<?php echo base_url() ?>products/send_inq',
                        data: {ref_prod:ref_prod, customer_name:customer_name, customer_email:customer_email},
                        success:function(data)
                        {
                            alert('Thanks...Your message sent successfully...We will keep in touch with you soon!!');
                        },
                        error:function()
                        {
                            alert('Sorry..!!! Your message is not submitted.');
                        }
                    });
                });
            });
        </script>

查看

<form action="" method="POST" id="send-inquiry" name="send-inquiry">

    <div class="row">
      <div class="col-sm-12">
          <div class="form-group">

              <input type="text" name="ref" class="form-control" id="ref_prod" value="<?php echo $product_item['product_name']; ?>(<?php echo $product_item['product_code']; ?>)" readonly>
          </div><!-- End .form-group -->
      </div><!-- End .col-sm-6 -->
        <div class="col-sm-12">
            <div class="form-group">

                <input type="text" name="customer_name" class="form-control" id="customer_name" placeholder="Name*" required>
            </div><!-- End .form-group -->
        </div><!-- End .col-sm-6 -->
        <div class="col-sm-12">
            <div class="form-group">

                <input type="text" name="customer_no" class="form-control" id="customer_no" placeholder="Mobile*" required>
            </div><!-- End .form-group -->
        </div><!-- End .col-sm-6 -->
        <div class="col-sm-12">
            <div class="form-group">

                <input type="email" name="customer_email" class="form-control" id="customer_email" placeholder="E-mail*" required>
            </div><!-- End .form-group -->
        </div><!-- End .col-sm-6 -->
    </div><!-- End .row -->

    <div class="form-group mb20">

        <textarea cols="30" name="comment" rows="5" id="comment" placeholder="Remark..." class="form-control"></textarea>
    </div>

    <div class="text-right">
        <input type="submit" id="submit-p" name="submit-p" class="btn btn-accent min-width" value="Submit">
    </div><!-- End .text-right -->
</form>

未提交Codeigniter 3.x Ajax表单

0 个答案: