Question

我做了一个id的列表，每个值是一个int类型

temp_id = [7922, 7018, 5650, 209, 21928, 2294, 10507, 3623]

type(tempasn) 
list

这有效：

Temp = pd.read_sql("select count(*) as count\
                    from "+db+"\
                    where ids in (7922, 7018, 5650, 209, 21928, 2294, 10507, 3623)\
                    order by count desc limit 10", conn)

我要获取列表的变量并将其添加到查询中

这会导致错误

Temp = pd.read_sql("select count(*) as count\
                    from "+db+"\
                    where ids in "+temp_id+"\
                    order by count desc limit 10", conn)


TypeError: Can't convert 'list' object to str implicitly

我不明白我需要在这里更改

答案

最后考虑了下面的评论，并修改了我的生成temp_id的循环：

temp_id = []
for id in df['ID']:
    if id and id not in temp_id:
        temp_id.append(str(ID))        

        #Convert to list format
temp_id = ", ".join(temp_id)

有2件事使这项工作成功了：

str(ID) & temp_id = ", ".join(temp_id)

Answer 1

您需要一个字符串，以便内嵌数组

temp_id = [7922, 7018, 5650, 209, 21928, 2294, 10507, 3623]


my_string = ",".join(temp_id )

Temp = pd.read_sql("select count(*) as count\
                    from "+db+"\
                    where ids in ("+my_string+")\
                    order by count desc limit 10", conn)

Answer 2

您需要将变量存储为逗号分隔的字符串而不是数组。

因此，将temp_id声明为字符串。

temp_id = "7922, 7018, 5650, 209, 21928, 2294, 10507, 3623"

Temp = pd.read_sql("select count(*) as count\
                    from "+db+"\
                    where ids in ("+temp_id+")\
                    order by count desc limit 10", conn)

带有列表变量的熊猫查询

2 个答案: