Question

我试图寻找解决方案，但似乎无法理解我遇到的问题。

我有一个搜索查询，其中带有“ where子句”，说明用户输入的多个单词是否返回结果。

我需要以搜索到的相同顺序返回结果。

即使我只添加了“ ORDER BY DESC”，也会引发“试图获取非对象的属性”错误。

这是我的代码：

$word = $_GET['word'];
$word3 = $_GET['word'];
$word = explode(";", $word);
$noOfWords = count($word);
$word2 = $word3;

if ($noOfWords == 1) {
    $searchString = " word_eng LIKE '" . $conn->escape_string($word3)  
        "%'";
} else {
    $searchString = $whereClause = "";
    foreach ($word as $entry) {
        $searchString .= " OR word_eng LIKE '" . $conn->escape_string($entry) . "' ORDER BY '" . $word2 . "' ";
    }
}

$whereClause = ($searchString != "") ? " WHERE " . preg_replace('/OR/', 
        '', $searchString, 1) : $whereClause;


$sql = "SELECT word_eng FROM words " . $whereClause . " LIMIT 17";

$result = $conn->query($sql);

if ($result->num_rows > 0) { 

    while($row = $result->fetch_assoc()) { 

        $row1 = $row["word_eng"];

        echo $row1;     


    }

Answer 1

尝试使用ORDER BY的方式存在两个问题。任何SQL中只能有1个order by子句，您要为添加的每个单词添加该子句。第二部分是期望按列名排序，并按搜索词排序。

由于想要保持术语的顺序和结果的顺序，因此有必要使用带有case之类的order by子句（Can you add an if statement in ORDER BY?可能有助于解释这一点）。

$orderBy = "";

if ($noOfWords == 1) {
    $searchString = " word_eng LIKE '" . $conn->escape_string($word3) ."%'";
} else {
    $searchString = $whereClause = "";
    $orderBy = " order by case `word_eng` ";
    foreach ($word as $order=>$entry) {
        $searchString .= " OR word_eng LIKE '" . $conn->escape_string($entry) . "'";
        $orderBy .= " when '$entry' then $order ";
    }
    $orderBy .= " end ";
}

$whereClause = ($searchString != "") ? " WHERE " . preg_replace('/OR/',
    '', $searchString, 1) : $whereClause;


$sql = "SELECT word_eng FROM words " . $whereClause . " " .$orderBy." LIMIT 17";

Answer 2

if ($noOfWords == 1) {
    $searchString = " word_eng LIKE '" . $conn->escape_string($word3)  
    "%'";
} else {
    $searchString = $whereClause = "";
    foreach ($word as $entry) {
        $searchString .= " OR word_eng LIKE '" . $conn->escape_string($entry);
    }
    $searchString .= "' ORDER BY '" . $word2 . "' ";
}

Answer 3

我认为您搞砸了下面一行代码中的MySQL查询字符串。

$searchString .= " OR word_eng LIKE '" . $conn->escape_string($entry) . "' ORDER BY '" . $word2 . "' ";

您的查询正在生成

之类的内容

ORDER BY DESC

“按订单查询”应该是这样的

ORDER BY expression [ ASC | DESC ];

因此您缺少查询中的表达式。

PHP SQL：按用户输入顺序对搜索查询结果进行排序

3 个答案: