Question

我是python的初学者。我正在尝试从python flask应用程序连接到Mongo DB服务器。但是由于遇到以下问题，我无法运行该应用程序。

from flask import Flask, render_template
from flask_pymongo import PyMongo
from pymongo import MongoClient # Database connector

app=Flask(__name__)

app.config["MONGO_DBNAME"]="connect_to_pymon"
app.config["MONGO_URI"]="mongodb://mongo_test:mongo_test@123@ds129821.mlab.com:29821/connect_to_pymon"
mongo = PyMongo(app)

@app.route("/add")
def add():

    user = mongo.db.users
    user.insert[{"name":"kishor"}]
    return "users added!"

if __name__=='__main__':
    app.run(debug=True, port=8080)

这是我的源代码。当我执行此操作时，出现以下错误，无法跟踪它。

Traceback (most recent call last):
  File "C:/Users/kravi/PycharmProjects/GitUploadTest/mongoTest.py", line 9, in <module>
    mongo = PyMongo(app)
  File "C:\Kishor\Training\My_Workspace\Python_Basics\TaskCRUD\venv\lib\site-packages\flask_pymongo\__init__.py", line 116, in __init__
    self.init_app(app, uri, *args, **kwargs)
  File "C:\Kishor\Training\My_Workspace\Python_Basics\TaskCRUD\venv\lib\site-packages\flask_pymongo\__init__.py", line 149, in init_app
    parsed_uri = uri_parser.parse_uri(uri)
  File "C:\Kishor\Training\My_Workspace\Python_Basics\TaskCRUD\venv\lib\site-packages\pymongo\uri_parser.py", line 379, in parse_uri
    user, passwd = parse_userinfo(userinfo)
  File "C:\Kishor\Training\My_Workspace\Python_Basics\TaskCRUD\venv\lib\site-packages\pymongo\uri_parser.py", line 97, in parse_userinfo
    "RFC 3986, use %s()." % quote_fn)
pymongo.errors.InvalidURI: Username and password must be escaped according to RFC 3986, use urllib.parse.quote_plus().

Process finished with exit code 1

注意：我尚未在PC中安装mongoDb。我正在使用mongo db作为服务

Answer 1

您可以使用PyMongo如下连接数据库：

from pymongo import MongoClient

client = MongoClient("mongodb://mongo_test:mongo_test@123@ds129821.mlab.com:29821/connect_to_pymon")

db = client["dbname"] # connect_to_pymon in your case

Answer 2

我了解到，在密码中使用特殊字符（如“ @”）没有意义，因为我们必须配置mongo URI，它具有带有@符号的特定格式。我更改了数据库密码，然后尝试了。！

从Python Flask应用程序连接到Mongo Server

2 个答案: