Question

我有一个表单，用户可以在其中放置网站网址，并需要获取其地理位置和标题，例如：https://www.site24x7.com/find-website-location.html 我是Rails的新手，不确定是否可以通过Geokit做到这一点。任何人都可以帮助如何开始处理它？</ p>

Answer 1

您可以使用普通的旧Ruby来处理大部分内容。您可以使用各种gem来处理它...但是依赖越少，您就会越好！这是一个例子...

# put this in the lib directory and name it location.rb
module Location
  require 'socket'
  require 'net/http'
  require 'json'

  def get_ip_address(url)
    IPSocket::getaddress(url)
  end

  def get_location_info(url)
    ip_address = get_ip_address(url)
    location = Net::HTTP.get(URI("https://ipapi.co/#{ip_address}/json/"))
    JSON.parse(location)
  end

  module_function :get_ip_address
  module_function :get_location_info
end

从get_location_info方法返回的JSON看起来像这样。...

{"ip"=>"108.163.210.34", "city"=>"Chicago", "region"=>"Illinois",
 "region_code"=>"IL", "country"=>"US", "country_name"=>"United States", 
"continent_code"=>"NA", "in_eu"=>false, "postal"=>"60604", "latitude"=>41.8776,
 "longitude"=>-87.6272, "timezone"=>"America/Chicago", "utc_offset"=>"-0500",
 "country_calling_code"=>"+1", "currency"=>"USD", "languages"=>"en-US,es-US,haw,fr", "asn"=>"AS32475", "org"=>"SingleHop LLC"}

因此，现在您可以在控制器中require 'location'并使用此方法获取信息

# at the top of your controller require 'location' 
def show
  # use a form that passes in the url to this show action to make it availabe in the params
  location_info = Location.get_location_info(params[:url])
  @ip = location_info["ip"]
  @city = location_info["city"]
  # other info you want to display in the view from location_info
end

RAILS获取网站地理位置和标题

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