Question

我是xml（c＃net mvc）的新手，我无法从Xml文件读取数据。我有复杂的数据类型，这是我的xml文件：

<Contour>
 <Elements>  
  <Element Type="Point" Indice="859">Route marseille<Limites>
  <Haut>26.5</Haut>
  <Bas>43.2</Bas>
  </Limites>
  <Point id="01"    X="45"  Y="44" >12</Point>
  <Point id="02"    X="5"   Y="41" >5</Point>
  <Point id="03"    X="4"   Y="464" >3</Point>
  </Element>
 <Element Type="Point" Indice="256">Route Bordeaux<Limites>
  <Haut>16.5</Haut>
  <Bas>12.2</Bas>
  </Limites>
  <Point id="05"    X="6.5" Y="22" >5</Point>
  <Point id="06"    X="58"  Y="46.5">5</Point>
  <Point id="07"    X="98"  Y="4.5" >6</Point>
  </Element>
  </Elements>
  </Contour>

Answer 1

您可以使用XmlDocument从字符串或文件中读取XML。

xmlDoc.LoadXml("<Contour>....</Contour>");

或

var node = xmlDoc.DocumentElement.SelectSingleNode("/Elements/Element");

然后找到具有以下内容的节点：

string type = node.Attributes["Type"]?.InnerText;

读取节点的属性：

string text = node.InnerText;

读取节点的文本：

$ gem dependency mysql2 --reverse-dependencies

这里是指向更完整的http://homepage.tudelft.nl/h05k3/Projects/MeshThickeningProj.htm

的链接

和answer

Answer 2

使用Xml Linq

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            List<Element> elements = doc.Descendants("Element").Select(x => new Element() {
                type = (string)x.Attribute("Type"),
                indice = (int)x.Attribute("Indice"),
                name = x.FirstNode.ToString(),
                haut = (decimal)x.Descendants ("Haut").FirstOrDefault(),
                bas = (decimal)x.Descendants("Bas").FirstOrDefault(),
                points = x.Elements("Point").Select(y => new Point() {
                    id = (string)y.Attribute("id"),
                    x = (decimal)y.Attribute("X"),
                    y = (decimal)y.Attribute("Y"),
                    value = (int)y
                }).ToList()
            }).ToList();
        }
    }
    public class Element
    {
        public string type { get; set; }
        public int indice { get; set; }
        public string name { get; set; }
        public decimal haut { get; set; }
        public decimal bas { get; set; }
        public List<Point> points { get; set;}
    }
    public class Point
    {
        public string id { get; set; }
        public decimal x { get; set; }
        public decimal y { get; set; }
        public int value { get; set; }
    }
}

这是使用Xml放入数据表的结果

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.Data;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            DataTable dt = new DataTable();
            dt.Columns.Add("Type", typeof(string));
            dt.Columns.Add("Indice", typeof(int));
            dt.Columns.Add("Name", typeof(string));
            dt.Columns.Add("Haut", typeof(decimal));
            dt.Columns.Add("Bas", typeof(decimal));
            dt.Columns.Add("Id", typeof(string));
            dt.Columns.Add("X", typeof(decimal));
            dt.Columns.Add("Y", typeof(decimal));
            dt.Columns.Add("Value", typeof(int));

            XDocument doc = XDocument.Load(FILENAME);

            foreach(XElement element in doc.Descendants("Element"))
            {
                string type = (string)element.Attribute("Type");
                int indice = (int)element.Attribute("Indice");
                string name = element.FirstNode.ToString();
                decimal haut = (decimal)element.Descendants("Haut").FirstOrDefault();
                decimal bas = (decimal)element.Descendants("Bas").FirstOrDefault();

                foreach(XElement point in element.Elements("Point"))
                {
                    string id = (string)point.Attribute("id");
                    decimal x = (decimal)point.Attribute("X");
                    decimal y = (decimal)point.Attribute("Y");
                    int value = (int)point;

                    dt.Rows.Add(new object[] { type, indice, name, haut, bas, id, x, y, value});
                }
            }
        }
    }

}

使用数据集从XML复杂数据类型中提取数据

2 个答案: