Question

经过过滤后，我得到以下结果：

[{SV2: "2*3"},{SV2: "3*4"},{SV2: "50"},{RV2: "10"},{RV2: "7*5"},{RV2: "50"}]

但是我想让所有对象具有与一个数组相同的键：

[{SV2: ["2*3","3*4","50"]},{RV2: ["10","7*5","50"]}]

在将信息发送到前端之前，如何在视图/序列化器中执行此操作？

型号：

class ProcessedStockAmounts(models.Model):
    prodName = models.ForeignKey(Productlist, on_delete=models.CASCADE, blank=False, unique=False, related_name='prod')
    amount = models.CharField(unique=True, max_length=255)
    time = models.ForeignKey(StockTakingTimes, on_delete=models.CASCADE, blank=False, unique=False, default=1)

序列化器：

class ProcessedStockSerializer(serializers.ModelSerializer):
    slug_field='productid', required=False)
    name = serializers.CharField(source='prodName')

    class Meta:
        model = ProcessedStockAmounts
        fields = '__all__'

    def to_representation(self, instance):
        result = super(ProcessedStockSerializer, self).to_representation(instance)
        new_result = {result['name']: result['amount']}
        return new_result

查看：

class ProcessedStockTimeView(generics.ListCreateAPIView):

    serializer_class = ProcessedStockSerializer 

    def get_queryset(self):
        time = self.kwargs['stock']
        value = ProcessedStockAmounts.objects.filter(time__times__icontains=time)
        return value

过滤后的Django将具有相同键的对象分组为一个键

0 个答案: