我在一些人的帮助下编写了这种表结构和查询，它的工作原理非常完美。我想获得两个日期之间的期初和期末余额。我已注释了要获取日期的日期，如果运行该日期，请检查所需的预期输出，如下所示。
以下是结构和示例数据：
DROP TABLE [TransactionMaster];
DROP TABLE [VoucherType];
CREATE TABLE [VoucherType](
[VoucherTypeCode] [tinyint] NOT NULL PRIMARY KEY,
[FullName] [nvarchar](255) NOT NULL
);
INSERT INTO [VoucherType] VALUES (1, 'Cash Payment Voucher');
INSERT INTO [VoucherType] VALUES (2, 'Cash Receipt Voucher');
INSERT INTO [VoucherType] VALUES (3, 'Bank Payment Voucher');
INSERT INTO [VoucherType] VALUES (4, 'Bank Receipt Voucher');
CREATE TABLE [TransactionMaster](
[ID] [bigint] NOT NULL PRIMARY KEY,
[VoucherTypeCode] [tinyint] NOT NULL,
[PayeeName] [varchar](255) NOT NULL,
[TransactionDate] datetime,
[Amount] NUMERIC,
[RefNo] [nvarchar](50) NULL
CONSTRAINT [FK_tbl_TransactionMaster_tbl_VoucherType] FOREIGN KEY([VoucherTypeCode])
REFERENCES [VoucherType] ([VoucherTypeCode])
)
INSERT INTO [TransactionMaster] VALUES (1, 2, 'Asim', '2018-03-21', '2500', 'CRV-0001-LHR');
INSERT INTO [TransactionMaster] VALUES (2, 4, 'Ali', '2018-03-21', '1150', 'BRV-2421-KHI');
INSERT INTO [TransactionMaster] VALUES (3, 1, 'Erick', '2018-03-23', '1200', 'CPV-5435-ISL');
INSERT INTO [TransactionMaster] VALUES (4, 3, 'Asim', '2018-03-24', '1000', 'BPV-2345-CAN');
INSERT INTO [TransactionMaster] VALUES (5, 2, 'Mehboob', '2018-03-25', '2400', 'CRV-2976-PSH');
INSERT INTO [TransactionMaster] VALUES (6, 1, 'Erick', '2018-03-25', '2900', 'CPV-2323-KOH');
INSERT INTO [TransactionMaster] VALUES (7, 1, 'Feroze', '2018-03-21', '3100', 'CRV-0531-SRG');
INSERT INTO [TransactionMaster] VALUES (8, 3, 'Ali', '2018-03-21', '500', 'BRV-2001-RWP');
这是查询
with data1 as (
select a.id inid,a.VoucherTypeCode,PayeeName,a.Amount InAmount,TransactionDate,RefNo,FullName from TransactionMaster a inner join [VoucherType] b on a.VoucherTypeCode = b.VoucherTypeCode
where a.VoucherTypeCode in (1,3)
),
data2 as (
select a.id outid,a.VoucherTypeCode,PayeeName,a.Amount OutAmount,TransactionDate,RefNo,FullName from TransactionMaster a inner join [VoucherType] b on a.VoucherTypeCode = b.VoucherTypeCode
where a.VoucherTypeCode in (2,4)
)
select *,COALESCE(a.TransactionDate,b.TransactionDate) as FullDate from data1 a full join data2 b on inid = outid and a.TransactionDate = b.TransactionDate
--WHERE COALESCE(a.TransactionDate,b.TransactionDate) BETWEEN '2018-03-23 00:00:00.000' AND '2018-03-24 00:00:00.000'
order by FullDate
现在的输出是这样的：
inid VoucherTypeCode PayeeName InAmount TransactionDate RefNo FullName outid VoucherTypeCode PayeeName OutAmount TransactionDate RefNo FullName FullDate
-------------------- --------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- --------------------------------------- ----------------------- -------------------------------------------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- -------------------- --------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- --------------------------------------- ----------------------- -------------------------------------------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- -----------------------
7 1 Feroze 3100 2018-03-21 00:00:00.000 CRV-0531-SRG Cash Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-21 00:00:00.000
8 3 Ali 500 2018-03-21 00:00:00.000 BRV-2001-RWP Bank Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-21 00:00:00.000
NULL NULL NULL NULL NULL NULL NULL 2 4 Ali 1150 2018-03-21 00:00:00.000 BRV-2421-KHI Bank Receipt Voucher 2018-03-21 00:00:00.000
NULL NULL NULL NULL NULL NULL NULL 1 2 Asim 2500 2018-03-21 00:00:00.000 CRV-0001-LHR Cash Receipt Voucher 2018-03-21 00:00:00.000
3 1 Erick 1200 2018-03-23 00:00:00.000 CPV-5435-ISL Cash Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-23 00:00:00.000
4 3 Asim 1000 2018-03-24 00:00:00.000 BPV-2345-CAN Bank Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-24 00:00:00.000
6 1 Erick 2900 2018-03-25 00:00:00.000 CPV-2323-KOH Cash Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-25 00:00:00.000
NULL NULL NULL NULL NULL NULL NULL 5 2 Mehboob 2400 2018-03-25 00:00:00.000 CRV-2976-PSH Cash Receipt Voucher 2018-03-25 00:00:00.000
预期输出是这样：
inid VoucherTypeCode PayeeName InAmount TransactionDate RefNo FullName outid VoucherTypeCode PayeeName OutAmount TransactionDate RefNo FullName FullDate Opening
-------------------- --------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- --------------------------------------- ----------------------- -------------------------------------------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- -------------------- --------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- --------------------------------------- ----------------------- -------------------------------------------------- --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- -----------------------
3 1 Erick 1200 2018-03-23 00:00:00.000 CPV-5435-ISL Cash Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-23 00:00:00.000 -50
4 3 Asim 1000 2018-03-24 00:00:00.000 BPV-2345-CAN Bank Payment Voucher NULL NULL NULL NULL NULL NULL NULL 2018-03-24 00:00:00.000 1150
公式为(Opening+InAmount) - Out Amount将是Closing Balance，而Opening将是前一行Closing Balance。
因此，对于第一个记录，打开将为0，关闭将为3100，而对于第二个打开= 3100，将关闭3600，依此类推。
答案 0 :(得分：2)
使用OUTER APPLY计算日期之前的金额。
使用条件SUM()来计算金额
select *
from [TransactionMaster] m
inner join [VoucherType] t on m.VoucherTypeCode = t.VoucherTypeCode
outer apply
(
select Opening = sum(case when [VoucherTypeCode] in (1, 3)
then Amount
else -Amount
end)
from [TransactionMaster] x
where x.TransactionDate < m.TransactionDate
) o
where m.TransactionDate between '2018-03-23' and '2018-03-24'
order by ID
对CASE WHEN语句的解释
根据VoucherTypeCode，金额被视为IN或OUT。
对于代码1和3，它是IN /正，其他是OUT /负
case语句的作用是根据VoucherTypeCode将金额转换为正值或负值
SELECT VoucherTypeCode, Amount
case when [VoucherTypeCode] in (1, 3)
then +Amount
else -Amount
end
FROM ...
基本上，您会得到
1 2 2500 -2500
2 4 1150 -1150
3 1 1200 1200
所以当您对SUM（）求和时，它将是-2500-1150 + 1200 +。