Question

我有一本包含清单的字典

    students = {
1:["name1", 20, 100],
2:["name2", 20, 100],
3:["name3", 20, 95],
4:["name4", 21, 65],
5:["name5", 22, 85]
}

我想创建表并按名称对数据进行排序。像这样

Name        Age       Score
name1       20        100
name2       20        100
name3       20        95
name4       21        65
name5       22        85

我该怎么做？我这样写：

students = {
1:["Rauf", 20, 100],
2:["Shafag", 20, 100],
3:["Ali", 20, 95],
4:["Camal", 21, 65],
5:["Arzu", 22, 85]

}
print(" ")
print("{:>12} {:>12} {:>12}".format('Name','Age','Score'))
print(" ")
for v in students.values():
    name, age, score = v
    print(sorted(("{:>12} {:>12} {:>12}".format(name, age, score)), key= lambda v: v[2]))

Answer 1

此帮助

import operator
students = {
1:["Rauf", 20, 100],
2:["Shafag", 20, 100],
3:["Ali", 20, 95],
4:["Camal", 21, 65],
5:["Arzu", 22, 85]

}
print(" ")
print("{:>12} {:>12} {:>12}".format('Name','Age','Score'))
sorted_students = sorted(students.items(), key=operator.itemgetter(1))
print(" ")
for v in sorted_students:
    name, age, score = v[1]
    print("{:>12} {:>12} {:>12}".format(name, age, score))

Answer 2

使用f字符串（Python 3.6+）和map，您可以简化语法并提高代码效率。您需要sorted才能按名称排序。

import operator
students = {1:["Rauf", 20, 100],
            2:["Shafag", 20, 100],
            3:["Ali", 20, 95],
            4:["Camal", 21, 65],
            5:["Arzu", 22, 85]}

print(" ")
print(f"{'Name':>12} {'Age':>12} {'Score':>12}")
sorted_students = sorted(students.items(), key=operator.itemgetter(1))
print(" ")
for name, age, score in map(itemgetter(1), sorted_students):
    print(f"{name:>12} {age:>12} {score:>12}")

结果：

    Name          Age        Score

     Ali           20           95
    Arzu           22           85
   Camal           21           65
    Rauf           20          100
  Shafag           20          100

创建表并根据字典中的列表对数据进行排序

2 个答案: