Question

我目前正面临一堵墙，我试图从两个不同的表中获取信息，让它们与按计数记录的信息并排显示。一个是第一个表中具有特定值的总量，第二个是不同列的值

表A.current与B.id相同

但是我想要的信息是当前表A中的总匹配数，并显示B.name信息而不是b.id

我已经尝试了很多事情，到目前为止，我仍然遇到一个问题，它说关于from是不正确的或组是不正确的...

select  count(pk.id) as "Total",
    lc.fullyqualifiedname as "Name"
from    tsu pk,
    location lc
where   pk.locationid = lc.id
group by lc.id
having lc.id  = :ID;

从上面的代码中，我收到错误00923

如果有人可以帮助我-我在哪里出错了？

我最终需要做的是

第1列-位置为lc.id的总命中数（count（*））第2列-正在显示lc.id表示为完全限定名称的名称。提供貂皮表中另一列的值。

编辑：

select  count(pk.id) as "Total",
    lc.fullyqualifiedname as "Name"
from    tsu pk,
    location lc
where   pk.locationid = lc.id
group by lc.id
having lc.id  = :ID;

此脚本有效，但是它显示了表lc中的第1列，我想从lc中获得列名。

-问题通过已回答的脚本解决。

Answer 1

对于单个lc.id，无需使用GROUP BY：

select count(pk.id) as "Total",
       min(lc.fullyqualifiedname) as "Name"   -- here agg function
from tsu pk
join location lc                              -- join syntax is preferred
  on pk.locationid = lc.id
where lc.id  = :ID;                           -- filtering with where

或者：

select count(pk.id) as "Total",
       min(lc.fullyqualifiedname) as "Name",
       lc.id
from tsu pk
join location lc
  on pk.locationid = lc.id
---where lc.id IN (...)
group by lc.id;

Answer 2

问题是lc.fullyqualifiedname出现在select列表中，但没有出现在group by子句中，因此出现在ORA-00979: not a GROUP BY expression中。

select count(pk.id) as "Total",
       lc.fullyqualifiedname as "Name"
from   tsu pk,
       location lc
where  pk.locationid = lc.id
and    lc.id  = :id
group by lc.fullyqualifiedname;

或更妙的是

select count(*) as "Total",
       lc.fullyqualifiedname as "Name"
from   tsu pk
       join location lc on lc.id = pk.locationid
where  lc.id  = 1
group by lc.fullyqualifiedname;

如果这不是您所需要的，请提供一些示例数据和预期结果。

Oracle 12 SQL-ORA-00933，ORA-0923，ORA-00979我在做什么错了？

2 个答案: