我正在开发一个基于Cordova的Web应用程序。我有一些svg模板。我想在用户点击屏幕时绘制用户点之间的路径。当用户点击svg内路径标签上的 时,我无法获得准确的xy坐标。但是,当用户在主svg空间上单击时,其工作正常。请给我任何想法或解决方案。请在下面检查代码-
这是一个svg模板代码-
<div style="height:82vh">
<p style="text-align:center;margin:0px;padding-top:10px"> Ground Floor</p>
<svg id="final" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" width="82vw" height="78vh"
viewBox="0 0 950 430" onclick="testsetNavigationPath(evt)">
<defs>
<filter id="dropshadow">
<feOffset result="offOut" in="SourceGraphic" dx="10" dy="10" />
<feColorMatrix result="matrixOut" in="offOut" type="matrix" values="0.2 0 0 0 0 0 0.2 0 0 0 0 0 0.2 0 0 0 0 0 1 0" />
<feGaussianBlur result="blurOut" in="matrixOut" stdDeviation="50" />
<feBlend in="SourceGraphic" in2="blurOut" mode="normal" />
</filter>
</defs>
<g id="gFinal" transform="matrix(0.72,0,0,-0.72,13,720)" >
<g transform="scale(0.1,0.1)" id="g12">
<path id="parking01".../>
.
.
.
.
</g>
</g>
</svg>
和这是js代码-
function testsetNavigationPath(evt) {
debugger
var e = document.getElementById('body');
var scope = angular.element(e).scope();
var svg = document.getElementById('final');
NS = svg.getAttribute('xmlns');
var
t = evt.target,
x = evt.clientX,
y = evt.clientY,
target = (t == svg ? svg : t.parentNode),
svgP = svgPoint(target, x, y),
circle = document.createElementNS(NS, 'circle');
console.log("click coordinates"+ Math.round(svgP.x) + ","+ Math.round(svgP.y));
circle.setAttributeNS(null, 'cx', Math.round(svgP.x));
circle.setAttributeNS(null, 'cy', Math.round(svgP.y));
circle.setAttributeNS(null, 'r', 10);
target.appendChild(circle);
scope.check = parseInt(scope.check) + 1;
if(parseInt(scope.check)<= 1){
pathAttr = 'M ' + Math.round(svgP.x) + ' ' + Math.round(svgP.y);
scope.dPath = scope.dPath + pathAttr;
}
else{
pathAttr = ' L ' + Math.round(svgP.x) + ' ' + Math.round(svgP.y);
scope.dPath = scope.dPath + pathAttr;
}
if(parseInt(scope.check) > 3){
testnavigateFromHome(scope.dPath);// this function draw the path based on points.
}
}
//**getting svg coordinates**
function svgPoint(element, x, y) {
var svg = document.getElementById('final')
var pt = svg.createSVGPoint();
pt.x = x;
pt.y = y;
return pt.matrixTransform(element.getScreenCTM().inverse());
}
此图像显示了当用户单击主svg空间时它可以正常工作。 但是用户单击svg path,它将拉出侧面屏幕。这意味着xy坐标在路径标签上不准确。所以它指出了一些地方。第二张图片-
答案 0 :(得分:0)