使用JSON格式从网站获取数据

时间:2018-07-05 22:17:30

标签: ios json swift

我想从代码中提到的网站获取数据,但是我遇到了一个错误,并且我不知道该怎么做才能解决它。 有谁可以帮助我吗? 谢谢

这些是我使用的代码

 @IBAction func onGetTapped(_ sender: Any) {
   guard let url = URL(string: "http://gpsforanimal.herokuapp.com/") else { return }
 let session = URLSession.shared
 session.dataTask(with: url) { (data, response, error) in
                if let response = response {
                    print(response)
                }
                if let data = data {
                    print(data)
                    do {
                        let json = try JSONSerialization.jsonObject(with: data, options: []) as? [String:Any]
                        print(json)
                    } catch {
                        print(error)
                    }

                }
            }.resume()
        }

我明白了

<NSHTTPURLResponse: 0x16d47ac0> { URL: http://gpsforanimal.herokuapp.com/ } { status code: 200, headers {
    "Cache-Control" = "max-age=0, private, must-revalidate";
    Connection = "keep-alive";
    "Content-Length" = 17536;
    "Content-Type" = "text/html; charset=utf-8";
    Date = "Thu, 05 Jul 2018 21:57:30 GMT";
    Etag = "W/\"cde6bf7e5688b2395a936b5785c715c4\"";
    Server = "WEBrick/1.3.1 (Ruby/2.2.6/2016-11-15)";
    "Set-Cookie" = "_GPS_session=MkZTb1NWQmp1QnA5MXFpUHQ3Wk1NdHV6Vm5ESjNGR1M5cC9jMUkxRTFVQXFuU1VTWko0R2F2a29WV3hNMzczcTAzVjB2TmpBTG5QbGFwcUVObnFHTEp5T0J6NWlFNXNBZ1ZJT1M4R3ZxRWthTzV4RUswalk3eDlrME1mc09KRGZlYzhLaGwxSlh1aGVXcDlPaFF4Vi9RPT0tLUNzNHpzUlVHSXFkZ3czZThyZU9ZMlE9PQ%3D%3D--c9fbcde23b38905f956d4a139629c710565d1015; path=/; HttpOnly";
    Via = "1.1 vegur";
    "X-Content-Type-Options" = nosniff;
    "X-Frame-Options" = SAMEORIGIN;
    "X-Request-Id" = "c2c9432e-37dd-4f44-9d10-62314f2c8ebc";
    "X-Runtime" = "0.040508";
    "X-Xss-Protection" = "1; mode=block";
} }
17536 bytes
Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn’t be completed. (Cocoa error 3840.)" (JSON text did not start with array or object and option to allow fragments not set.) UserInfo=0x16d63c60 {NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.}

4 个答案:

答案 0 :(得分:2)

尝试:

func getURL(){
    var request = URLRequest(url: URL(string: "http://gpsforanimal.herokuapp.com/positions.json")!)
    request.httpMethod = "GET"
    let session = URLSession.shared
    session.dataTask(with: request) {data, response, error in
        if error != nil {
            print(error!.localizedDescription)
        }
        guard let data = data else { return }
        do {
            //Decode retrived data with JSONDecoder and assing type of Article object
            let realData = try JSONDecoder().decode([gps].self, from: data)
            print(realData)
        } catch let jsonError {
            print(jsonError)
        }
        }.resume()
}

并创建一个带有可编码的结构,如下所示:

struct gps : Codable{
    var id = Int()
    var longitude  : String?
    var latitude : String?
    var created_at = String()
    var updated_at = String()
    var url = String()

    init(){
        self.id = Int()
        self.longitude = String()
        self.latitude  = String()
        self.created_at = String()
        self.updated_at = String()
        self.url = String()
    }
}

,然后调用您的函数 getURL()

答案 1 :(得分:2)

对于swift4.1,无需初始化

func getURL(){
    var request = URLRequest(url: URL(string: "http://gpsforanimal.herokuapp.com/positions.json")!)
    request.httpMethod = "GET"
    let session = URLSession.shared
    session.dataTask(with: request) {data, response, error in
        if error != nil {
            print(error!.localizedDescription)
        }
        guard let data = data else { return }
        do {
            //Decode retrived data with JSONDecoder and assing type of Article object
            let decoder = JSONDecoder()
            decoder.keyDecodingStrategy = .convertFromSnakeCase
            let realData = try decoder.decode([gps].self, from: data)
            print(realData)
        } catch let jsonError {
            print(jsonError)
        }
        }.resume()
}

创建一个结构:

struct gps : Decodable{
    var id :Int
    var longitude  : String?
    var latitude : String?
    var createdAt : String
    var updatedAt : String
    var url : String
 }

答案 2 :(得分:0)

您能否将URL更改为http://gpsforanimal.herokuapp.com/positions.json,然后重试;

您提供的URL返回了JSON的表格呈现,您需要提取JSON而不是表格。

答案 3 :(得分:-2)

尝试使用AlamoFire获取数据。您可以使用SwiftyJSON分析并更好地从网站的JSON响应中获取数据。