我将NestJs框架与Sequelize Typescript一起用于Node,我试图在用户和网页之间创建多对多关系,使许多用户可以在其收藏夹中拥有相同的网站
现在我的问题是,当我进行查询时,它会将结果限制为单个条目,而直接使用完全相同的查询直接查询数据库时,则会返回所有预期的条目。
这是我的NestJs收藏夹实体,在其中定义了收藏夹表:
// favorite.entity.ts
import { Table, Column, Model, PrimaryKey, ForeignKey, BelongsTo, NotNull } from "sequelize-typescript";
import { IDefineOptions } from "sequelize-typescript/lib/interfaces/IDefineOptions";
import { UserEntity } from "../users/user.entity";
import { SiteEntity } from "../sites/site.entity";
const tableOptions: IDefineOptions = {
timestamp: true,
tableName: "favorites",
schema: process.env.DB_SCHEMA,
} as IDefineOptions;
@Table(tableOptions)
export class FavoriteEntity extends Model<FavoriteEntity> {
@BelongsTo(() => UserEntity)
user: UserEntity;
@ForeignKey(() => UserEntity)
@PrimaryKey
@NotNull
@Column
userId: number;
@BelongsTo(() => SiteEntity)
site: SiteEntity;
@ForeignKey(() => SiteEntity)
@PrimaryKey
@NotNull
@Column
siteId: number;
}
我进行Sequelize查询的服务:
// favorite.service.ts
import { Inject, Injectable } from "@nestjs/common";
import { Model } from "sequelize-typescript";
import { IFavoriteService } from "./interfaces";
import { FavoriteEntity } from "./favorite.entity";
@Injectable()
export class FavoriteService implements IFavoriteService {
constructor(
@Inject("FavoriteRepository") private readonly favoriteRepository: typeof Model,
@Inject("SequelizeInstance") private readonly sequelizeInstance,
) {}
public async findByUserId(userId: number): Promise<FavoriteEntity | null> {
return await FavoriteEntity.scope().find<FavoriteEntity>({
logging: console.log,
where: { userId },
});
}
}
已注销的SQL语句为:
Executing (default): SELECT "userId", "siteId" FROM "public"."favorites" AS "FavoriteEntity" WHERE "FavoriteEntity"."userId" = '1';
结果是一个条目(数据库中有很多行)...
{
"userId": 1,
"siteId": 1650
}
我是否在实体中犯了一些错误,或者可能是在我的续集查询中?
谢谢!
答案 0 :(得分:0)
mottosson您确定同一条SQL查询返回很多行吗?因为那会很奇怪。
答案 1 :(得分:0)
如果您使用findAll
而不是find
,会得到什么结果。但是我同意查询看起来不错