我想使用JSON发送POST请求,我期望JSON对象带有auth_token和refresh_token作为响应。我的代码如下:
let headers: HTTPHeaders = [
"Authorization": "Basic " + data.toBase64() //data is just string needed for authentication
]
// this should be a JSON
let parameters = [
"code": self.code,
"grant_type": "authorization_code",
"redirect_uri": "populi://callback"
]
Alamofire.request("https://populi.pl/api/v1/auth/token", method: .post, parameters: parameters, encoding: JSONEncoding.default, headers: headers).responseString { response in
print(response.request)
print("\n3 RESPONSE : \(response)")
print("\n3 POST : \(response.response)")
print("\n3 DATA : \(response.data)")
print("\n3 RESPONSE RESULT : \(response.result)")
print("\n3 RESPONSE RESULT VALUE : \(response.result.value)")
print("3 ERROR : \(response.error)")
}
是的,我打印了很多东西,这是因为我是网络新手。 作为回应,我将永久性地迁移301。为什么?我不知道怎么了这是参数中的错误JSON还是带有重定向功能?我应该得到200和JSON作为响应。
答案 0 :(得分:0)
尝试
func getData(){
let todoEndpoint: String = Your url
let params: Parameters = [yor parameters]
let headers: [String : String] = [
"Content-Type": "application/x-www-form-urlencoded",
]
Alamofire.request(todoEndpoint, method: .post, parameters: params,headers: headers)
.responseJSON { response in
switch response.result {
case .success:
let json = JSON(response.result.value as Any)
print(json)
break
case .failure(let error):
print(error)
}
}
}
答案 1 :(得分:0)
我在请求网址末尾用“ /”解决了这个问题。