Question

我只想在窗口中显示一个浮点数组，我使用的代码是：

CvSize size;
size.height = HEIGHT ; //(640)
size.width = WIDTH; //(1680)
IplImage* ipl_image_p = cvCreateImageHeader(size, IPL_DEPTH_32F, 1);
ipl_image_p->imageData = (char*)my_float_image_data; //imageData only accepts char*
ipl_image_p->imageDataOrigin = ipl_image_p->imageData;


cvNamedWindow("Image", 1);
cvShowImage("Image", ipl_image_p);
cvWaitKey(0);
cvDestroyAllWindows();

弹出的图像全白。我做错了什么？

由于

编辑：

感谢Martin Beckett快速回答这个问题。我也有与16位图像相同的问题，是否链接？（我的图片范围从0到1000）

unsigned short* temp = new unsigned short[HEIGHT*WIDTH];
for(int i = 0 ; i < HEIGHT*WIDTH; i++){
    temp[i] = (unsigned short)my_float_image_data[i];
}

CvSize size;
size.height = HEIGHT ;
size.width = DISPLAY_DATA_WIDTH;
IplImage* ipl_image_p = cvCreateImageHeader(size, IPL_DEPTH_16U, 1);
ipl_image_p->imageData = (char*)temp;
ipl_image_p->imageDataOrigin = ipl_image_p->imageData;

cvNamedWindow("Image", 1);
cvShowImage("Image", ipl_image_p);
cvWaitKey(0);
cvDestroyAllWindows();

Answer 1

如果值在0-1

之间，OpenCV只能显示浮点图像

您的浮动数据范围是什么？

Answer 2

假设您的字符已经格式化为浮点数是否安全？

浮点颜色从0.0到1.0，uchars从0到255.以下代码修复它：

// h is height, w is width, c is current channel (0 to 2)
int b = ((uchar *)(img->imageData + h*img->widthStep))[w*img->nChannels + c];
((float *)(img2->imageData + h*img2->widthStep))[w*img2->nChannels + c] = ((float)b) / 255.0;

这也可能有所帮助：How to convert an 8-bit OpenCV IplImage* to a 32-bit IplImage*?

使用OpenCV显示浮点数组时出现问题

2 个答案: