将XML转换为JSon到c#对象

时间:2018-07-05 18:35:28

标签: c# json xml

作为动态文档处理程序应用程序的一部分,我们必须将数千个文档从XML迁移到Json。这是我的方法。

我有这个Xml

<?xml version="1.0"?>
    <syscur_historial_schema>
        <strtipoobj>OM_SECCION</strtipoobj>
        <strnombreobj>_1_Seccion_IDENTIFICACION_DEL_PACIENTE</strnombreobj>
        <numobj>0.00</numobj>
        <txtpropsobj/>
        <txtprostit><![CDATA[BackColor = 14171687,BorderStyle = 0,FontBold = .F.,FontItalic = .F.,FontName = "Tahoma",FontSize = 9,FontUnderline = .F.,ForeColor = 0,AutoSize = .F.,BackStyle = 1,LineColor = 14171687, TitleWidth=100, CAPTION="IDENTIFICACION DEL PACIENTE"]]>
        </txtprostit>
        <strencabezado>IDENTIFICACION DEL PACIENTE</strencabezado>
    </syscur_historial_schema>

我将其转换为JSon:

enter image description here

然后我需要将该JSon反序列化为c#类:

public class syscur_historial_schema
{
    public string strtipoobj { get; set; }
    public string strnombreobj { get; set; }
    public string numobj { get; set; }
    public string txtpropsobj { get; set; }
    public string txtprostit { get; set; }
    public string strencabezado { get; set; }
}

这是我的转换器:

public class ConvertXmlToJson
{
    /// <summary>
    /// Convierte un archivo con formato XML en fornato JSon 
    /// usando JsonConvert.SerializeXmlNode(doc)
    /// </summary>
    /// <param name="xmlPath"></param>
    /// <returns></returns>
    public static string XmlToJsonSerializeXmlNode<T>(string xmlPath, string nodeName, bool cleanString)
    {
        string justPath = Path.GetDirectoryName(xmlPath);
        string json = Path.Combine(justPath, $"{Path.GetFileNameWithoutExtension(xmlPath)}.json");
        XmlDocument doc = new XmlDocument();

        if (cleanString)
            doc.LoadXml(CleanRepeatedSpaces(File.ReadAllText(xmlPath)));
        else
            doc.LoadXml(File.ReadAllText(xmlPath));

        XmlNodeList nodes = GetNode(doc, nodeName);
        List<T> lista = new List<T>();
        foreach (XmlNode node in nodes)
        {
            string jSonNode = JsonConvert.SerializeXmlNode(node);
            T obj = JsonConvert.DeserializeObject<T>(jSonNode);
            lista.Add(obj);
        }
        File.WriteAllText(json, JsonConvert.SerializeObject(lista));
        return json;
    }

    public static XmlNodeList GetNode(XmlDocument doc, string nodeName)
    {
        XmlNodeList nodes = doc.GetElementsByTagName(nodeName);
        return nodes;
    }
}    

此测试方法

[TestMethod]
public void Tools_ConvertXmlToJson_Tests()
{
    string path = "D:\\MyXmlPath\\";
    string xml = Path.Combine(path, "MyXmlFile.hist");
    string jsonFile = ConvertXmlToJson.XmlToJsonSerializeXmlNode<syscur_historial_schema>(xml, "syscur_historial_schema",true);
    Assert.AreEqual(true, File.Exists(jsonFile));
    List<syscur_historial_schema> jsonObject = JsonConvert.DeserializeObject<List<syscur_historial_schema>>(File.ReadAllText(jsonFile));
}

现在我的问题是我的反序列化对象在每个属性上总是返回null,我一直认为问题是CDATA节点。

问题

1-我做错了什么?

2-如何将xml CDATA转换为Json字符串?

1 个答案:

答案 0 :(得分:2)

使您的syscur_historial_schema类序列化为这样:

[Serializeable]     
public class syscur_historial_schema
{
 public string strtipoobj { get; set; }
 public string strnombreobj { get; set; }
 public string numobj { get; set; }
 public string txtpropsobj { get; set; }
 public string txtprostit { get; set; }
 public string strencabezado { get; set; }
}

然后将xml反序列化为此类:

XmlSerializer serializer = new XmlSerializer(typeof(syscur_historial_schema));

StreamReader reader = new StreamReader(xmlPath);
var schema = (syscur_historial_schema)serializer.Deserialize(reader);
reader.Close();

然后像这样将架构转换为json:

 string json = JsonConverter.SerializeObject(schema);

在将其转换为类对象之前,无需将xml字符串转换为xml文档。直接将xml字符串反序列化为类对象。