Question

同一帐户具有不同的不同状态，而其他则具有相同的状态。如何在T-SQl中做到这一点

Account Status
1000001185  A
1000001185  E 
1000001185  E 
1000001185  D
1000001777  E 
1000001777  E 
1000001777  E 
1000001185  E

Answer 1

您可以：

select Account, (case when min(Status) = max(Status) 
                      then min(Status) 
                      else 'other' 
                  end)
from table t
group by Account;

Here是一个SQL Fiddle，表明此解决方案是正确的。

Answer 2

试试这个，我使用Lead（）函数

;WITH CTE(Account, [Status])
AS
(
SELECT '1000001185','A' UNION ALL
SELECT '1000001185','E' UNION ALL 
SELECT '1000001185','E' UNION ALL 
SELECT '1000001185','D' UNION ALL
SELECT '1000001777','E' UNION ALL 
SELECT '1000001777','E' UNION ALL 
SELECT '1000001777','E' UNION ALL 
SELECT '1000001185','E' 
)
SELECT Account,[Status],CASE WHEN [Status]<>LEAD([Status],1)OVER(PARTITION BY Account ORDER BY Account)
            THEN 'Other' ELSE [Status] END [NewStatus]
 FROM Cte 

 ORDER BY cte.[Status]

结果

 Account    Status       NewStatus
 -------------------------------------
1000001185      A           A
1000001185      D           Other
1000001185      E           Other
1000001185      E           E
1000001185      E           Other
1000001777      E           E
1000001777      E           E
1000001777      E           E

同一帐户的状态不同，其他则相同。如何在T-SQl中执行此操作

2 个答案: