Question

当我得到结果时，我得到的是数组格式的结果，这使我无法以所需的格式发布值。

我需要采用所需格式的结果（这些输入是从while循环中获取的）：

<html>
<form>
<input type=text name=ref_id[] value=abc>
<input type=text name=qty[] value=12>
<input type=submit name=submit>

PHP脚本：

$data1 = array(
'delv_num' => $delv_num,
'hu_id' => $hu_id,
'box_scan_value' => $box_scan_value,
'type' => $type,
'hu_detail'=> array(
'reference_id'=> $_POST['ref_id'],
'qty' => $_POST['qty'] )
  );
echo json_encode($data1);

我得到的结果如下：

{
"delv_num":"0006020715",
"hu_id":"HU000000000000000225",
"box_scan_value":"68889",
"type":"box",
"hu_detail":{
"reference_id":["TD0000000000991","TD0000000000990","TD0000000000767"],
"qty":["2","0","0"]
}
}

但是我需要以下格式的结果：

{
"delv_num":"0006020715",
"hu_id":"HU000000000000000225",
"box_scan_value":"68889",
"type":"box",
"hu_detail":[{
"reference_id":"TD0000000000991",
"qty":"2"
},
{
"reference_id":"TD0000000000990",
"qty":"0"
},
{
"reference_id":"TD0000000000767",
"qty":"0"
}
]
}

预先感谢

Answer 1

您应该能够自己执行此操作。如果没有，则应再次通过php-basics：

$complete = [
    'delv_num'       => $delv_num,
    'hu_id'          => $hu_id,
    'box_scan_value' => $box_scan_value,
    'type'           => $type,
    'hu_detail' => []
];
foreach ($_POST['ref_id'] as $index => $refId) {
    $huDetail = [
        'reference_id'=> $refId,
        'qty' => $_POST['qty'][$index]
    ];
    $complete['hu_detail'][] = $huDetail;
}

echo json_encode($complete);

Answer 2

只需更改输入名称即可更改表单的结构

function one(val) {
  let result = '';

  switch (val) {
    case 'alpha':
      result = 'Adams';
      break;
    case 'bravo':
      result = 'Boston';
      break;
  };

  return result;
}


function two(val) {
  const lookup = {
    'alpha': 'Adams',
    'bravo': 'Boston',
  };

  return lookup[val] || '';
}


console.log('one:', one('alpha'));
console.log('two:', two('alpha'));

Answer 3

尝试这样

$references =  $_POST['ref_id'];
$qtys = $_POST['qty'];

$data = array(
'delv_num' => $delv_num,
'hu_id' => $hu_id,
'box_scan_value' => $box_scan_value,
'type' => $type,
);

$huDetails = [];

foreach($references as $index => $ref){
   $huDetails[$index]['ref'] = $ref;
   $huDetails[$index]['qty'] = $qtys[$index]; //assuming you have `ref` and `qty` has same number of index, if not then you need to modify your html structure
}

$data['hu_details'] = $huDetails;

print_r(json_encode($data))

Answer 4

尝试这个：

$result = array();
$array_a = array("1","2","3");

$array_b = array("test1","test2","test3");

foreach($array_a as $key=> $value){
  $result[$key]['reference_id'] = $value;
  $result[$key]['qty'] = $array_b[$key];
}

$myJSONString = json_encode($result);

Answer 5

在单个语句中可能的解决方案：

$data1 = [
    'delv_num' => $delv_num,
    'hu_id' => $hu_id,
    'box_scan_value' => $box_scan_value,
    'type' => $type,
    'hu_detail' => array_map(
         function ($id, $qty) {
             return ['reference_id': $id, 'qty': $qty];
         },
         $_POST['ref_id'],
         $_POST['qty']
    ),
];

$ _POST方法的JSON打印结果

5 个答案: