列中的值重复时进行透视

Question

此查询的结果：

+--------------------------------------+-----------+--------+
|                  id                  |   name    |  data  |
+--------------------------------------+-----------+--------+
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | LMP1(FA5) | NULL   |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Limits    | NULL   |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Low       | 1      |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | High      | 3      |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Units     | second |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Comp      | GELE   |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Data      | 1.8    |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Status    | Passed |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | LMP2(FA6) | NULL   |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Limits    | NULL   |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Low       | 1      |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | High      | 3      |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Units     | second |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Comp      | GELE   |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Data      | 1.8    |
| 4EAB4160-75FF-11E8-8719-2C56DC925591 | Status    | Passed |
+--------------------------------------+-----------+--------+

我想得到这个：

我已经尝试过了，但是不是绝对的答案：

SELECT *
FROM
(
SELECT  id, name, data as f FROM temp_id)t
PIVOT(MIN(f)
      FOR name
      IN ([LMP1 (FA5)],[Limits],[Low],[High],[Units],[Comp],[data],[Status])
      )p

最好也有动态列的名称...

我感谢大家的帮助。

我已经尝试过这种动态枢纽，但它不起作用：

DECLARE @cols AS NVARCHAR(MAX), @query  AS NVARCHAR(MAX);

 SET @cols = STUFF((SELECT ',' + QUOTENAME(c.name) 
            FROM temp_id c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT id,' + @cols + ' from 
            (
                select id
                    , name
                    , data
                from temp_id
           ) x
            pivot 
            (
                count(name)
                for name in (' + @cols + ')
            ) p