Question

这是我的模特：

SELECT "fields_count" / SUM("fields_count") AS not_able_to_use_SUM_with_field , "error" FROM ( 
    SELECT COUNT("some_unique_data") AS fields_count AS fields_sum FROM "my_measument" WHERE $timeFilter GROUP BY "error"
)

现在，我需要向namespace App; use Illuminate\Database\Eloquent\Model; class purchase_order extends Model { protected $table = "purchase_order"; public $timestamps = false; public function commodities() { return $this->hasMany(commodities::class, 'purchase_order_id', 'id'); } }方法中再添加一个条件。实际上，我需要说的是它返回commodities()并返回commodities。如何将此where子句添加到关系中？

Answer 1

最好的方法是将invoiced()的查询范围添加到您的Commodities模型中。

https://laravel.com/docs/5.6/eloquent#query-scopes

因此，在您的Commodities模型上，您可以添加：

public function scopeInvoiced($query){
    return $query->where('invoiced', 1);
}

然后使用Commodities->invoiced();

Answer 2

您可以执行此操作，但可以参考关系表，如下所示：

public function commodities()
{
    return $this->hasMany(commodities::class, 'purchase_order_id', 'id')
        ->where('commodities.invoiced', 1);
}

构建查询时，它也会在commodities.invoiced处进行查询

参考：https://laraveldaily.com/filter-eloquent-relationships-fly-need/

如何在Laravel关系中添加where子句？

2 个答案: