这是我的代码。
if UIDevice().userInterfaceIdiom == .phone {
switch UIScreen.main.nativeBounds.height {
case 1136:
print("iPhone 5 or 5S or 5C")
self.pageControl = UIPageControl(
frame: CGRect(
x: 0,
y: 502 ,
width: self.view.frame.size.width,
height: 17
)
)
case 1334:
print("iPhone 6/6S/7/8")
self.pageControl = UIPageControl(
frame: CGRect(
x: 0,
y: 601 ,
width: self.view.frame.size.width,
height: 17
)
)
case 1920, 2208:
print("iPhone 6+/6S+/7+/8+")
self.pageControl = UIPageControl(
frame: CGRect(
x: 0,
y: 670 ,
width: self.view.frame.size.width,
height: 17
)
)
case 2436:
print("iPhone X")
default:
print("unknown")
}
}
if UIDevice().userInterfaceIdiom == .pad {
switch UIScreen.main.nativeBounds.height {
case 1024:
self.pageControl = UIPageControl(
frame: CGRect(
x: 0,
y: 50 ,
width: self.view.frame.size.width,
height: 17
)
)
default:
print("unknown")
}
}
这里是iphone时,页面控件将按照上面的代码显示。现在我需要在ipad中执行相同的操作。如果发现它是ipad,则将页面控件放在我需要的位置。
但是问题是:-
if UIDevice().userInterfaceIdiom == .pad {
switch UIScreen.main.nativeBounds.height {
case 1024:
self.pageControl = UIPageControl(
frame: CGRect(
x: 0,
y: 50 ,
width: self.view.frame.size.width,
height: 17
)
)
default:
print("unknown")
}
我在这里需要:-
那怎么给?
答案 0 :(得分:0)
根据我们检测到所有设备的情况,这非常容易。
#define iPadPro ([[UIDevice currentDevice] userInterfaceIdiom] ==
UIUserInterfaceIdiomPad && [UIScreen mainScreen].bounds.size.height ==
1366)
#define iPadPro12 (UIDevice.currentDevice.userInterfaceIdiom ==
UIUserInterfaceIdiomPad &&
UIScreen.mainScreen.nativeBounds.size.height == 2732)