我正在尝试从Servlet页面到jsp页面获取数据,但是却得到了空值。 我想获取servlet页面中的消息。 请帮助我 下面是我的代码 servlet:
package com.project1;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/TestServlet")
public class TestServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public TestServlet() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String msg="hi i am servlet";
request.setAttribute("data",msg);
request.getRequestDispatcher("Test.jsp").forward(request, response);
}
}
这是我的jsp代码:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<div>
<%= request.getAttribute("data") %>.
</div>
</body>
</html>
答案 0 :(得分:0)
您的代码正在运行。 servlet。
您错过了doGet方法中的 @override 。
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
//processRequest(request, response);
String msg = "hi i am servlet";
request.setAttribute("data", msg);
request.getRequestDispatcher("Test.jsp").forward(request, response);
}
Test.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<div>
<%=request.getAttribute("data")%>.
</div>
</body>
</html>
也许添加
@WebServlet(name =“ TestServlet”,urlPatterns = {“ / TestServlet”})
到servlet的顶部