Question

我已经做到了，但是它的静态数据存储在两个数组中。

 private void GetGraph() {
    LineGraphSeries<DataPoint> series = new LineGraphSeries<DataPoint>(new DataPoint[]{
            new DataPoint(first[0], second[0]),
            new DataPoint(first[1], second[1]),
            new DataPoint(first[2], second[2]),
            new DataPoint(first[3], second[3]),
            new DataPoint(first[4], second[4]),
            new DataPoint(first[5], second[5]),
            new DataPoint(first[6], second[6]),
            new DataPoint(first[7], second[7]),
            new DataPoint(first[8], second[8]),
            new DataPoint(first[9], second[9]),
    });
    graph.getViewport().setScalable(true);
    graph.addSeries(series);

Answer 1

您可以使用随机函数生成一组可以传递给DataPoint的随机数。这是教程：- https://dzone.com/articles/random-number-generation-in-java

如何在graphchart上显示随机数据点？

1 个答案: