Question

在仅提示输入一个数字的情况下，我该怎么做？不是5个输入分开的数字？我无法循环播放（我们仅在学校的第二章中），即使我知道使用它更合乎逻辑：

分配只使用％或/来查找5位整数的和

 /*  while( Number > 0) {
    Remainder = Number % 10;
    Sum = Sum + Remainder;
    Number = Number / 10;
    System.out.format("sum: "+ Sum);
  */

也可以有人用外行的术语解释模数和/和。谢谢！

//Scanner is in the java.util package
import java.util.Scanner; //import class

public class SumOf5Digits {

private static Scanner input;

public static void main(String[] args) {
    input = new Scanner(System.in);

    System.out.print("Enter a 5-digit positive integer: ");
    int Number1, Remainder1;
    int Number2, Remainder2;
    int Number3, Remainder3;
    int Number4, Remainder4;
    int Number5, Remainder5;
    int Sum = 0;

    Number1 = input.nextInt();
    Number2 = input.nextInt();
    Number3 = input.nextInt();
    Number4 = input.nextInt();
    Number5 = input.nextInt();

    Remainder1 = Number1 % 10;
    Number1 = Number1 /10;
    Remainder2 = Number2 % 10;
    Number2 = Number2 /10;
    Remainder3 = Number3 % 10;
    Number3 = Number3 /10;
    Remainder4 = Number4 % 10;
    Number4 = Number4 /10;
    Remainder5 = Number5 % 10;
    Number5 = Number5 /10;

    Sum = Sum + (Remainder1 + Remainder2 + Remainder3 + Remainder4 + 
    Remainder5);

    System.out.format ("sum:" + Sum);

}

Answer 1

这里是一个例子：

import java.util.Scanner; //import class

public class SumOf5Digits {

  public static void main(String[] args) {

     // Read integer
     Scanner input = new Scanner(System.in);
     System.out.print("Enter a 5-digit positive integer: ");
     int number = input.nextInt();

     // Compute sum of up to five base-10 digits in the number
     int sum = 0;
     if (number > 99999) {
        System.out.println("WARNING: " + number + " has more than five base-10 digits");
     } else {
       int digit = number % 10;  System.out.println("digit[0]=" + digit);
       sum += digit;
       digit = (number/10) % 10;  System.out.println("digit[1]=" + digit);
       sum += digit;
       digit = (number/100) % 10;  System.out.println("digit[2]=" + digit);
       sum += digit;
       digit = (number/1000) % 10;  System.out.println("digit[3]=" + digit);
       sum += digit;
       digit = (number/10000) % 10;  System.out.println("digit[4]=" + digit);
       sum += digit;
     }

     // Print sum
     System.out.println("Sum=" + sum);
  }
}

示例输出：

Enter a 5-digit positive integer: 22222
digit[0]=2
digit[1]=2
digit[2]=2
digit[3]=2
digit[4]=2
Sum=10

查找5个正整数之和（一个输入）而无需循环

1 个答案: