Question

考虑一个名为“ Customer”的超大表的示例：

CustomerID   | LastName | FirstName | Address | City |
-------------|----------|-----------|---------|------|
1520         | Guere    |Francisco  |XPTO     |London|**
2214         | Santos   |António    |TUDO     |Porto |
3998         | Freixe   |Luís       |IUPO     |Quebec|
1520         | Guere    |Francisco  |XPTO     |Rome  |**
5691         | Anton    |Ana        |TIDI     |Lisbon|
1520         | Guere    |Francisco  |XPTO     |Rome  |**

从这个小例子中可以看出，对于同一位客户（CustomerID = 1520），“城市”列中的值是不同的。

例如，在这种情况下，所需的输出将是：

 CustomerID | City |
 -----------|------|
 1520       |London|
 1520       |Rome  |

我试图开发一个查询，该查询返回在City列中具有不同值的CustomerID。

SELECT CustomerID, City 
FROM (SELECT CustomerID, COUNT(DISTINCT City) FROM Customer GROUP BY CustomerID) 
WHERE City > 1

有人可以帮助我解决我开发的查询的问题吗？

Answer 1

如果需要城市，可以使用exists：

select c.*
from customers c
where exists (select 1
              from customers c2
              where c2.customerid = c.customerid and c2.city <> c.city
             );

或者，如果您只想要客户，则可以使用group by：

select customerid
from customers
group by customerid
having min(city) <> max(city);

Answer 2

您可以使用HAVING进行过滤：

SELECT *
FROM Customer
WHERE CustomerID IN(SELECT CustomerID
                    FROM Customer 
                    GROUP BY CustomerID
                    HAVING COUNT(DISTINCT City) > 1);

Answer 3

您可以使用以下内容：

SELECT CustomerID, City
FROM Customer
WHERE CustomerID IN (
  SELECT CustomerID
  FROM Customer
  GROUP BY CustomerID
  HAVING COUNT(DISTINCT City) > 1
)
GROUP BY CustomerID, City;

结果：

| CustomerID | City   |
|------------|--------|
| 1520       | London |
| 1520       | Rome   |

如何从表中选择重复项

3 个答案: