编辑：

Question

表t为

|id| sport      |
|1 | football   |
|1 | football   |
|1 | baseball   |
|2 | football   |
|2 | football   |
|3 | football   |
|4 | football   |
|4 | golf       |
|4 | golf       |
|4 | baseball   |
|4 | football   |
|5 | football   |
|5 | football   |
|6 | basketball |
|6 | football   |
|6 | football   |

按id分组，我如何仅选择所有运动值=足球的ID？像这样

SELECT * FROM t 
GROUP BY id
HAVING ALL SPORT = 'football'

为了返回

|id| sport      |
|2 | football   |
|2 | football   |
|3 | football   |
|5 | football   |
|5 | football   |

Answer 1

您可以使用条件聚合：

SELECT *
FROM tab
WHERE id IN (SELECT id 
             FROM t 
             GROUP BY id
             HAVING SUM(CASE WHEN sport != 'football' THEN 1 ELSE 0 END) = 0);

编辑：

我需要进行哪些调整才能将...体育=足球的所有值转换为体育=足球的任何值？

SELECT *
FROM tab
WHERE id IN (SELECT id
             FROM t
             WHERE sport = 'football');

Answer 2

这是简单的解决方案：

SELECT *
FROM t
WHERE id IN (
    SELECT id
    FROM t
    GROUP BY id
    HAVING COUNT(CASE WHEN sport = 'football' THEN 1 END) = COUNT(*)
)

Answer 3

在所有值都相同的列中，最小值和最大值相等。您可以在having子句中使用此属性：

SELECT   id, MAX(sport)
FROM     t
GROUP BY id
HAVING   MIN(sport) = 'football' AND MAX(sport) = 'football'

Answer 4

如果要原始行，请使用not exists：

select t.*
from t
where t.sport = 'footbal' and
      not exists (select 1
                  from t2
                  where t2.id = t.id and t2.sport <> t.sport
                 );

否则，请使用

having min(sport) = max(sport) and max(sport) = 'football'

Answer 5

根据上述问题中的描述，作为解决方案，请尝试执行以下SQL select查询

    select * from(SELECT id, sport FROM `t`
        group by id, sport) as q group by q.id having count(q.id) = 1 
and sport = 'football'

查找给定列中所有值均与指定值匹配的组

5 个答案:

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