想象一下，我得到了以下结果：
>coef(model1)
Estimate Std. Error t-value Pr(>|t|)
X1 -1.3006813 1.962377480 -0.6628089 5.079128e-01
X2 -12.1455641 5.838937045 -2.0800985 3.828320e-02
X3 11.0701123 9.367725395 1.1817290 2.381590e-01
X4 3.2903167 0.690324322 4.7663346 2.810855e-06
X5 0.0240804 0.005345124 4.5051151 9.201743e-06
X6 0.1834814 0.047485944 3.8639097 1.341940e-04
和
>coef(model2)
Estimate Std. Error t-value Pr(>|t|)
X1 -1.3180103 1.962377480 -0.6628089 5.079128e-01
X2 -10.5006410 5.838937045 -2.0800985 3.828320e-02
和
>coef(model6)
Estimate Std. Error t-value Pr(>|t|)
X2 -1.3256782 1.962377480 -0.6628089 5.079128e-01
X6 -1.56931410 5.838937045 -2.0800985 3.828320e-02
我要做的是创建此表，其中每一行是每个模型的系数：
X1 X2 X3 X4 X5 X6
-1.300 -12.145 11.070 3.290 0.0240 0.183
-1.318 -10.500
-1.325 -1.569
有什么建议吗？
*理想情况下，我想添加一个* if p-value>0.05, ** if p-value>0.01 and *** if <0.01，以便立即将其与library(xtable)添加到乳胶中。
答案 0 :(得分：1)
我认为这可能会更加简洁，但是一开始您可以使用它。另外，我使用了舍入功能，因此-1.3006813在我的代码中变成了-1.301，而不是1.300。另外，请注意Pr...t..只是列名Pr(>|t|)的读入错误。
library(plyr)
library(dplyr)
library(tidyr)
myfunction <- function(x){
x %>%
mutate(Std. = round(Std., 3),
Std.Adjusted = ifelse(Pr...t.. > 0.05, paste0(Std., "*"), ifelse(Pr...t.. < 0.05 & Pr...t.. > 0.01, paste0(Std., "**"), paste0(Std., "***")))) %>%
select(Estimate, Std.Adjusted) %>%
spread(Estimate, Std.Adjusted)
}
rbind.fill(lapply(list(mod1,mod2,mod6), myfunction))
X1 X2 X3 X4 X5 X6
1 -1.301* -12.146** 11.07* 3.29*** 0.024*** 0.183***
2 -1.318* -10.501** <NA> <NA> <NA> <NA>
3 <NA> -1.326* <NA> <NA> <NA> -1.569**
mod1 <- read.table(text = "
Estimate Std. Error t-value Pr(>|t|)
X1 -1.3006813 1.962377480 -0.6628089 5.079128e-01
X2 -12.1455641 5.838937045 -2.0800985 3.828320e-02
X3 11.0701123 9.367725395 1.1817290 2.381590e-01
X4 3.2903167 0.690324322 4.7663346 2.810855e-06
X5 0.0240804 0.005345124 4.5051151 9.201743e-06
X6 0.1834814 0.047485944 3.8639097 1.341940e-04
", h = T)
mod2 <- read.table(text = "
Estimate Std. Error t-value Pr(>|t|)
X1 -1.3180103 1.962377480 -0.6628089 5.079128e-01
X2 -10.5006410 5.838937045 -2.0800985 3.828320e-02
", h = T)
mod6 <- read.table(text = "
Estimate Std. Error t-value Pr(>|t|)
X2 -1.3256782 1.962377480 -0.6628089 5.079128e-01
X6 -1.56931410 5.838937045 -2.0800985 3.828320e-02
", h = T)
答案 1 :(得分：1)
这有效：
library(tidyverse)
data <- list(model1, model2, model6)
data %>%
map_df(rownames_to_column, "Var", .id = 'Model') %>%
select(Model, Var, Estimate) %>%
spread(Var, Estimate)
|Model | X1| X2| X3| X4| X5| X6|
|:-----|---------:|----------:|--------:|--------:|---------:|----------:|
|1 | -1.300681| -12.145564| 11.07011| 3.290317| 0.0240804| 0.1834814|
|2 | -1.318010| -10.500641| NA| NA| NA| NA|
|3 | NA| -1.325678| NA| NA| NA| -1.5693141|
数据：
model1 <- read.table(text = "
Estimate Std.Error t-value Pr(>|t|)
X1 -1.3006813 1.962377480 -0.6628089 5.079128e-01
X2 -12.1455641 5.838937045 -2.0800985 3.828320e-02
X3 11.0701123 9.367725395 1.1817290 2.381590e-01
X4 3.2903167 0.690324322 4.7663346 2.810855e-06
X5 0.0240804 0.005345124 4.5051151 9.201743e-06
X6 0.1834814 0.047485944 3.8639097 1.341940e-04
", h = T)
model2 <- read.table(text = "
Estimate Std.Error t-value Pr(>|t|)
X1 -1.3180103 1.962377480 -0.6628089 5.079128e-01
X2 -10.5006410 5.838937045 -2.0800985 3.828320e-02
", h = T)
model6 <- read.table(text = "
Estimate Std.Error t-value Pr(>|t|)
X2 -1.3256782 1.962377480 -0.6628089 5.079128e-01
X6 -1.56931410 5.838937045 -2.0800985 3.828320e-02
", h = T)
不太清楚星星的意思，但是可以在管道中添加case_when语句来添加星星