使用python pandas style.where（或其他方式）为两列不匹配的特定单元格着色，并导出到excel

Question

我正在寻找不匹配的两列中特定单元格的颜色，但是我想将其与python pandas style.where一起使用，并使用openpyxl在excel中导出。

到目前为止，我的代码：

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我被卡住了，因为它会产生错误：

df = pd.DataFrame({
    'config_dummy1': ["dummytext"] * 100,
    'config_size_x': ["textstring"] * 100,
    'config_size_y': ["textstring"] * 100,
    'config_dummy2': ["dummytext"] * 100
})
df.at[50, 'config_size_x'] = "xandydontmatch"
df.at[99, 'config_size_y'] = "xandydontmatch"
print(df)
df.style.where(
    df['config_size_x'] != df['config_size_y'],
    'color: #ffffff; background-color: #ba3018',
    other=''
).to_excel('styled.xlsx', engine='openpyxl')

TypeError ：（““系列”对象不可调用”，“发生在索引config_dummy1处”

我愿意接受.where（）以外的建议，我也尝试使用.apply（）来做到这一点，但失败了。

注意：列索引位置不是固定的，可以是Traceback (most recent call last): File "python-match-csv.py", line 205, in <module> main2() File "python-match-csv.py", line 131, in main2 ).to_excel('styled.xlsx', engine='openpyxl') File "F:\Python36\lib\site-packages\pandas\io\formats\style.py", line 175, in to_excel engine=engine) File "F:\Python36\lib\site-packages\pandas\io\formats\excel.py", line 652, in write freeze_panes=freeze_panes) File "F:\Python36\lib\site-packages\pandas\io\excel.py", line 1390, in write_cells for cell in cells: File "F:\Python36\lib\site-packages\pandas\io\formats\excel.py", line 617, in get_formatted_cells self._format_body()): File "F:\Python36\lib\site-packages\pandas\io\formats\excel.py", line 529, in _format_regular_rows for cell in self._generate_body(coloffset): File "F:\Python36\lib\site-packages\pandas\io\formats\excel.py", line 601, in _generate_body styles = self.styler._compute().ctx File "F:\Python36\lib\site-packages\pandas\io\formats\style.py", line 514, in _compute r = func(self)(*args, **kwargs) File "F:\Python36\lib\site-packages\pandas\io\formats\style.py", line 604, in _applymap result = self.data.loc[subset].applymap(func) File "F:\Python36\lib\site-packages\pandas\core\frame.py", line 6072, in applymap return self.apply(infer) File "F:\Python36\lib\site-packages\pandas\core\frame.py", line 6014, in apply return op.get_result() File "F:\Python36\lib\site-packages\pandas\core\apply.py", line 318, in get_result return super(FrameRowApply, self).get_result() File "F:\Python36\lib\site-packages\pandas\core\apply.py", line 142, in get_result return self.apply_standard() File "F:\Python36\lib\site-packages\pandas\core\apply.py", line 248, in apply_standard self.apply_series_generator() File "F:\Python36\lib\site-packages\pandas\core\apply.py", line 277, in apply_series_generator results[i] = self.f(v) File "F:\Python36\lib\site-packages\pandas\core\frame.py", line 6070, in infer return lib.map_infer(x.astype(object).values, func) File "pandas/_libs/src\inference.pyx", line 1472, in pandas._libs.lib.map_infer File "F:\Python36\lib\site-packages\pandas\io\formats\style.py", line 671, in <lambda> return self.applymap(lambda val: value if cond(val) else other, TypeError: ("'Series' object is not callable", 'occurred at index config_dummy1') 或任何其他组合

注意2：如果需要，可以使用Windows和python 3.6

Answer 1

由于此问题被标记为styleframe：

from StyleFrame import StyleFrame, Styler

df = pd.DataFrame({'a': [1, 2], 'b': [1, 3]})

sf = StyleFrame(df)
sf.apply_style_by_indexes(sf[sf['a'] != sf['b']], styler_obj=Styler(bg_color='red'))
sf.to_excel('test.xlsx').save()

会产生

如果您只希望为不匹配的行中的一部分着色，则可以简单地使用cols_to_style参数：

sf.apply_style_by_indexes(sf[sf['a'] != sf['b']], styler_obj=Styler(bg_color='red'),
                          cols_to_style=['a', 'b'])

Answer 2

您可以使用apply创建样式的DataFrame：

def color(x):
    c1 = 'color: #ffffff; background-color: #ba3018'
    m = x['config_size_x'] != x['config_size_y']
    df1 = pd.DataFrame('', index=x.index, columns=x.columns)
    df1.loc[m, ['config_size_x', 'config_size_y']] = c1
    return df1

df.style.apply(color, axis=None)

一般解决方案：

df = pd.DataFrame({
    'config_dummy1': ["dummytext"] * 10,
    'a_y': ["a"] * 10,
    'config_size_x': ["textstring"] * 10,
    'config_size_y': ["textstring"] * 10,
    'config_dummy2': ["dummytext"] * 10,
    'a_x': ["a"] * 10
})
df.at[5, 'config_size_x'] = "xandydontmatch"
df.at[9, 'config_size_y'] = "xandydontmatch"
df.at[0, 'a_x'] = "xandydontmatch"
df.at[3, 'a_y'] = "xandydontmatch"
print(df)

def color(x):
    c1 = 'color: #ffffff; background-color: #ba3018'
    df1 = pd.DataFrame('', index=x.index, columns=x.columns)

    #select only columns ends with _x and _y and sorting
    cols = sorted(x.filter(regex='_x$|_y$').columns)
    #loop by pairs and assign style by mask
    for i, j in zip(cols[::2],cols[1::2]):
        #pairs columns 
        #print (i, j)
        m = x[i] != x[j]
        df1.loc[m, [i, j]] = c1
    return df1

df.style.apply(color, axis=None).to_excel('styled.xlsx', engine='openpyxl')